• 2022-05-26
    ‍关系模式STJ(S#,T,J#)中,存在函数依赖:(S#,J#)→T,(S#,T)→J#,T→J#,则( )。‌
    A: 关系STJ满足1NF,但不满足2NF
    B: 关系STJ满足2NF,但不满足3NF
    C: 关系STJ满足3NF,但不满足BCNF
    D: 关系STJ满足BCNF,但不满足4NF