• 2022-05-28
    设[tex=6.286x2.786]r5Haq7W1lVGBc4dFEM2Zk/eS7OKRFt9VQUTtxU/X5sGN1ApXDkF1QkGWehFHBRrW7GSbfuNRS7zZSowCc/hdWBuV42+J8l+ffzaJIsGMXPg=[/tex],[tex=6.286x2.786]k4XxnokJDFH17b6cU904x1L+ezwnamK5bBEWCJuqlAopN51IXkaGphU3tU9/CJQKYUAqxeY8E62iu+pPHDALKEqVAkkb8I+cmdjfQ57kvnM=[/tex],问[tex=10.714x1.5]I2C8f96vyoPzdVnGanJ2ljLHgrPO7tLook9ukCJBDYou0A300MIq7eb87oDK17aGZU+5u6B/nb3h7aZv2/DY9zlcTNpCw7fpXNJ3GJ4RpctHQK4Be997fcboD19jkiHGn7ElodXq4CFuujzeGNn8uA==[/tex]吗?
  • 解:[tex=7.429x1.357]I2C8f96vyoPzdVnGanJ2ljLHgrPO7tLook9ukCJBDYou0A300MIq7eb87oDK17aGZU+5u6B/nb3h7aZv2/DY9/rcPqey1yEmLmSSuV7QJck=[/tex][tex=10.071x2.786]jyVOORWehIbTNQvvtYroWpzG3VRALYELjiut2J8ZmG/W8vZjPiHdVTCGE6maT7s0lKbZ53RswzN6CaE4qQo95294mii3S1BXIvO0JYiQsbj7rozWmyECj7rA5SiRmsNJJ79CPpGhva3GmMD33qJ3lIUVWAqmMJF+u8ZTV/cY/bI=[/tex][tex=4.5x2.786]jyVOORWehIbTNQvvtYroWpjYVazmcJJAjwch09R+3fhJ6Oe2BqLWy56rtaENzNa3c8xXmaAiM9KA1cxB0ItrPQ==[/tex],[tex=4.071x1.357]r5Haq7W1lVGBc4dFEM2ZkzLG62YnMPhsvGTvbrFiq8sWfDZ2qmLtDBoUQvjEytK8[/tex][tex=11.5x2.786]jyVOORWehIbTNQvvtYroWrEyrGzUv4Vrt28ojATZFfiuLQ66biHynYPz9qUcI+feOQ1rqAlArPcMfO/vnpy9b03WGe+9Rr+m6uuX2mnTNfCt3aXI2AUmjptm3sXVjVpw8CtI9eiokjWF/cZNzK+zA8ZMtgDl26BmaVX+h5LgRcE=[/tex][tex=4.5x2.786]jyVOORWehIbTNQvvtYroWjesXV02YqDIlTghYwsYkPlJuBOsJqSR5niFvlxqvffStMg9ceDFNZggu5xZU5IT5A==[/tex]故[tex=11.214x1.5]I2C8f96vyoPzdVnGanJ2ljLHgrPO7tLook9ukCJBDYou0A300MIq7eb87oDK17aGZU+5u6B/nb3h7aZv2/DY90SlGkpCy3o0QCPeZHoL1p5wMYijEG/c2kgQPRaRLWWetF1SWPFWzzCtX4/QF1NeIg==[/tex]。

    举一反三

    内容

    • 0

      A=[1 2 3 4 5 6 7 8 9]A(5)=[]A=1 4 7 5 8 3 6 9

    • 1

      >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']

    • 2

      (1)5 7 9 11() () ()()(2)26 23 20 17()() 8()(3)1 2 4 7 11() () 29(4)7 3 8 3 9 3()()(5)1 1 2 3 5 8()()

    • 3

      以下程序的输出结果是___________。for i in range(1,11): print(i, end = " ") A: 1 2 3 4 5 6 7 8 9 B: 1 2 3 4 5 6 7 8 9 10 C: 1 2 3 4 5 D: 1 3 5 7 9

    • 4

      已知a=[1 2 3; 4 5 6; 7 8 9],执行命令:a([3,1],:)=a([1,3],:),a将变为( )。 A: [4 5 6;4 5 6;4 5 6] B: [7 8 9;4 5 6;1 2 3] C: [2 2 2;5 5 5;8 8 8] D: [3 2 1;6 5 4;9 8 7]