利用洛必达法则求下列极限：[tex=3.357x2.143]Wh0BbcsxbdPTUak0FdVk/ZQuyy7Fb48esTSmX0ITOc3HXeChcqk3ZJ4mZoRj3trR[/tex]
解 [tex=11.214x3.286]Wh0BbcsxbdPTUak0FdVk/UJDuwZPfUMmAr6H0zk0trXMj7CJBAQ4XtDBQ27zhBhVASjCZJR+GMI4LiBmcSHRDi+p5UZvRonI7y5ouMzWczcEdTW9TO26M8AhAdCbbwSKtHV7uO31HXco+YNYtmGBNF37rVKZAj71seEA5Gy8GrY=[/tex][tex=9.714x3.357]LJoZ6w1fh/2otaE2gK07/JYWB8egAWK0k4q59W6vxgZG9wZ6R1nMaC1qdtDvD8c95vuTJwy7618jqcYvamkdYv/4U/n3eTDT61ORksp/acXQ8BQX39SoKwngIUDAuvrOmM/TkhoETLMn4Lb5PDxDGkas1N3TSPguWcuqBcn99Zs=[/tex]
举一反三
- 利用洛必达法则求极限：[tex=3.357x2.143]MhC0sa4kP8ihnFHLNuEHS/MH3J3+ZOM/LvfHOBDDjCASGUcXjBzIhT6Wh0j3314O[/tex]
- 利用洛必达法则求下列极限：[tex=3.071x1.786]Wh0BbcsxbdPTUak0FdVk/avBOPtsBLXUGkOo/e4LxVSNfHffYfVZLRZrteytfcTA[/tex]；
- 利用洛必达法则求下列极限：[tex=4.643x1.786]Wh0BbcsxbdPTUak0FdVk/avBOPtsBLXUGkOo/e4LxVQfk3FLl+azNfOknguU1O+4[/tex]
- 利用洛必达法则求下列极限：[tex=6.571x2.0]Wh0BbcsxbdPTUak0FdVk/avBOPtsBLXUGkOo/e4LxVSQ/48RJ2ksrBl1B39oxyJZ[/tex]；
- 求极限[tex=5.714x2.429]Wh0BbcsxbdPTUak0FdVk/UF2rKTSeqk6MCwdvBGZxhPnApCD2PMfhUNY8w9B7vsRZiLrBMXmEkRQOFWIe7couw==[/tex]，下列解法（）正确. 未知类型：{'options': ['用洛必达法则，原式[tex=14.214x2.429]Wh0BbcsxbdPTUak0FdVk/UF2rKTSeqk6MCwdvBGZxhOvWGP43c+fXU8zbdrU4bLTStbjTIo+v5ZWxkOky7xCeV1UNJBkh/2FXrEe51AfAWTwFSi0GWnQv5maOv91z/v14DlBQUtTx/Qi9NEes99YOLFiRPSDA2YtSEI2mYspqag=[/tex]', '不用洛必达法则，极限不存在[tex=11.214x4.643]LJoZ6w1fh/2otaE2gK07/JaV8WvgiI/WyLeTeb4m6eZAcWIiZogzJjpMex7lW3BVmAX+FGDYcNGZFAo46zlGs69j1UF6uHAVsGXhXimLD/oaFE695g/5vlRqjsa1Xxk5r5Jo56M0Gw3AlehYSTX9DEaHc7HDJH23/jd/2FaX5ys=[/tex]', '不用洛必达法则，原式', '不用洛必达法则，原式=[tex=10.286x4.643]Wh0BbcsxbdPTUak0FdVk/UF2rKTSeqk6MCwdvBGZxhNiI49lr3h2iGXcMD+OiAFBnny8233+tuvV9oI2EOUVvtK1Xiox7NfIpoTSmA2bNQOXaTUsSZ8zS32tygb9vHqzGxVsyUneGbXAyT3si4kJhXNi3KhsrZYK6PU0yMs+Qd8=[/tex]'], 'type': 102}
内容
- 0
利用洛必达法则求极限：[tex=3.643x2.0]MhC0sa4kP8ihnFHLNuEHSy8dTKi6ves4OqsRQbRKX004s5igHAPtu2LAtwebTCl8[/tex]
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利用洛必达法则求极限:[tex=4.929x1.786]MhC0sa4kP8ihnFHLNuEHS+vrwio+K9FLrXqYqfa8I9crwGtrlJWEdZuILVF0iyvI[/tex]
- 2
利用洛必达法则求极限[tex=6.714x2.429]ENxIatiC2yqgaopSQCG83tXQk5xuU/AX5+Ac5mQsVp/0btTbHq5IhFNvBMambUoTKmuNkFAva4lwNAeXexoT+w==[/tex].
- 3
利用洛必达法则求极限：[tex=4.571x2.0]ENxIatiC2yqgaopSQCG83hcpU77eGXLTmd3S29CIk5T0kH/m2Ks4Wa1/MlbAFWXn[/tex]
- 4
洛必达法则求极限lim[e^x-e^(-x)]/sinxx→0limsin3x/sin5xx→0limxcot2xx→0