• 2022-07-23
    把下面复系数多项式分解为一次因式的乘积:[tex=27.357x1.429]pUQ4RLdeX+CWxzXtZ/VJBcZD68Rgxg6WMlp+SkW9tJTR/LpfwV59c1OXQ8tU73P9NGAoUioozWO6AB0+y0AdBa2MpSHg9Enn9fLj5E0+kf3ae8irEhswB6oJBlFF79kUbxzuiiBmfLCJXG7PWwfVI43me5cCqEndho67p3oR36jwrnN0nT9uyJBvCnNayiHF[/tex]。
  • 解:注意到[tex=27.357x1.429]pUQ4RLdeX+CWxzXtZ/VJBcZD68Rgxg6WMlp+SkW9tJTR/LpfwV59c1OXQ8tU73P9NGAoUioozWO6AB0+y0AdBa2MpSHg9Enn9fLj5E0+kf3ae8irEhswB6oJBlFF79kUbxzuiiBmfLCJXG7PWwfVI43me5cCqEndho67p3oR36jwrnN0nT9uyJBvCnNayiHF[/tex][tex=18.786x2.357]0a16d/jXRKstOlLQT/aW7x0KWFACg5vPeBb5uyJQLBCIG6VGpwG64bx9i6AmQwOpIpxyfb1XXQWBZLzTnPWccURdEKzPDFz1wMu7ZXeyWlwn/MwODu3GgiBlbLH67W89et9ANd+DewKi67LayZThaw==[/tex][tex=23.143x2.929]0a16d/jXRKstOlLQT/aW74KZ1AlqBt0CLSNYfES8T5zkeHZpY3cm31sZKYUKPmedJSk5CJT+G3Z48YZM0+ehgmUxONmUnppzpZVkmHE165x/wgMfasST0ZBGAyCI9pdq48YYxSRxStzeX3nNNZ2dhyD6EpY0bBr5tGQuzNpqpsbk4iS0z1t8z21by1UkNe6D[/tex]可知方程的解为[tex=11.571x2.786]b+MMKAgnbJh8REbFwiiKlEGqMNtfTWqhMgLFIs2XTlrdKFIw302tt4ULIt60Suc/xf0RlXKciJ3GSUH28c0O4XORtrtf/eHv6fRKEtghP3I=[/tex],即[tex=9.214x2.786]s5x6AdJ9MK2reV4TeNVIImw41ZWc5qdNqMvaC0cUwK3Dct2MKmycVW53E0qC2WMM[/tex],[tex=8.071x1.214]fsbQIftuV2kPT8O4JTsrRqk3o3bDcKBbvvlf9vBXDts=[/tex]于是[tex=27.357x1.429]pUQ4RLdeX+CWxzXtZ/VJBcZD68Rgxg6WMlp+SkW9tJTR/LpfwV59c1OXQ8tU73P9NGAoUioozWO6AB0+y0AdBa2MpSHg9Enn9fLj5E0+kf3ae8irEhswB6oJBlFF79kUbxzuiiBmfLCJXG7PWwfVI43me5cCqEndho67p3oR36jwrnN0nT9uyJBvCnNayiHF[/tex][tex=18.714x2.857]ukknskKOEif4KBAivJos9ETasgV+9CoP0ssqGR96YNiYo7a/h3kx9zTemGhIYuuFNcBQHLBRbkAdTVWLSJKyHQ8wBAx8M16rnw1Fm9i5u7LfWeNrLw3UU8/iLQU9+Ob522DM709ER9aw7U68tqt6oQ==[/tex]

    内容

    • 0

      【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背

    • 1

      输入10个整数存入一维数组a,然后按逆序重新存储数据,最后按顺序输出该数组,每个数据占5列。例如输入 2 5 6 7 1 8 9 0 3 6 后,a(0)-a(9)依次为2、5、6、7、1、8、9、0、3、6,逆序重新存储数据后a(0)-a(9)依次为6、3、0、9、8、1、7、6、5、2,输出应为 6 3 0 9 8 1 7 6 5 2 注意:语言选DEV C++

    • 2

      输出九九乘法表。 1 2 3 4 5 6 7 8 9 --------------------------------------------------------------------- 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9 9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81

    • 3

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}

    • 4

      当执行下面的语句定义一维数组a后,此数组的所有元素为 ( ) inta[10]; A.a[1],a[2],a[3],a[4],a[5],a[6],a[8],a[9],a[10],a[10] B.a[0],a[1],a[2],a[3],a[4],a[5],a[6],a[7],a[8],a[9] C.a[0],a[2],a[3],a[4],a[5],a[6],a[7],a[8],a[9],a[10] D.a[1],a[2],a [3],a[4],a [5],a [9],a [7],a [8],a [9],a [10],a [11]