• 2022-07-23
     设 [tex=19.214x1.357]stAv5ciwwUJG6qpOxbwl0bpHkApZF5fnBuMRSkEcp6+l5wvLd0bc5Ws173UKhwAB[/tex], [tex=4.857x1.214]gWRjkmdlRCgBEzTr1FAbBA/GJkPoKB5xz20cvWU4+YQ=[/tex] 证明[tex=12.429x1.357]gDvyJF6VQyXSUBj6BV+t3XIG/qGxXv++nOpeOWFtlUSxC+PsStrc1YBEAkehyJmxSA2NzOVxWV5pkXmlLn1hfw==[/tex]
  • 证明 由假设[tex=4.857x1.357]sdPqZDV1IROZXhztgyx7BQ==[/tex]都是[tex=4.143x1.357]jXxZMneg8YljyAKDckPdqQ==[/tex]的组合,余式[tex=4.143x1.357]jXxZMneg8YljyAKDckPdqQ==[/tex]的公因式都是[tex=4.857x1.357]sdPqZDV1IROZXhztgyx7BQ==[/tex]的公因式因为 [tex=4.857x1.214]gWRjkmdlRCgBEzTr1FAbBA/GJkPoKB5xz20cvWU4+YQ=[/tex] 所以[tex=14.786x5.357]qeiYnKXLEhyhuGRg8yLtr0l24jvL/MoNOZWLtKL67BQyoz3oX/4BeeNBVlyTXgw2VU/0y3tRLcLwLo6/XkBakPOqjUG9Iu+hIhc4dWlo0PbpQ9n+RuB0MQc9L0JUKrfBWwlcC5TW7yCWeRPyoJ0W23Db0TYswwzRbcvLRuJhY5NGK3lMdhquAPwOPjQTmkdql76jI2gaBy9WNuuafMS9AGYhj5WvXpzkSaY1YvGh0l0=[/tex]所以[tex=4.0x1.357]9L2r5tlh3JJ32yY4a6m3XQ==[/tex] 也都是 [tex=4.857x1.357]s1/lhScWuBdgN5kmu6molSktUrFZ1WdIRwobMwpcIIs=[/tex] 的组合.[tex=4.857x1.357]s1/lhScWuBdgN5kmu6molSktUrFZ1WdIRwobMwpcIIs=[/tex]的公因式也都是 [tex=4.0x1.357]9L2r5tlh3JJ32yY4a6m3XQ==[/tex]的公因式.所以[tex=11.714x1.357]V+4hUFywnEjqK7biHNq7Vff2zo++Iz+hyQ1xKNT963shiRv1ZFVIP5mwMwR2Cukb[/tex]

    内容

    • 0

        设 9 阶无向图 [tex=0.786x1.0]LyvDGollVJ+xwurtsLcn0g==[/tex] 中,每个顶点的度数不是 5 就是 6, 证明 : [tex=0.786x1.0]LyvDGollVJ+xwurtsLcn0g==[/tex] 中至少有 5 个 6 度顶点或至 少有 6 个5 度顶点.

    • 1

      求函数$y = {{1 + \root 3 \of {{x^2}} - \sqrt {2x} } \over {\sqrt x }}$的导数$y' = $( ) A: $ {1 \over 2}{x^{ - {3 \over 2}}} + {1 \over 6}{x^{ - {5 \over 6}}}$ B: $ - {1 \over 2}{x^{ - {3 \over 2}}} + {1 \over 6}{x^{ - {5 \over 6}}}$ C: ${1 \over 2}{x^{ - {3 \over 2}}} - {1 \over 6}{x^{ - {5 \over 6}}}$ D: ${1 \over 3}{x^{ - {3 \over 2}}} - {1 \over 6}{x^{ - {5 \over 6}}}$

    • 2

      >>>x = [1, 2, 3]>>>x.extend([5, 6, 7])语句运行结果正确的是( )。 A: [1, 2, 3, 5, 6, 7] B: [5, 6, 7, 1, 2, 3] C: [0, 1, 2, 3, 4, 5, 6, 7] D: [5, 6, 7]

    • 3

      设x=(8>1)+5,x的值为() A: 0 B: 1 C: 6 D: 5

    • 4

      >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']