When deriving stationary probabilities of Markov chain, we often use n + 1 equations to get ( ) stationary probabilities
A: n - 1
B: n
C: n + 1
D: n + 2
A: n - 1
B: n
C: n + 1
D: n + 2
举一反三
- 排列\( n(n - 1)(n - 2) \cdots 3 \cdot 2 \cdot 1 \)的逆序数是（ ） A: \( {1 \over 2}n(n - 1) \) B: \( n(n - 1) \) C: \( n \) D: \( {n^2}(n - 1) \)
- 已知()y()=()ln()x(),则()y()(()n())()=()。A.()(()−()1())()n()n()!()x()−()n()"()role="presentation">()(()−()1())()n()n()!()x()−()n();()B.()(()−()1())()n()(()n()−()1())()!()x()−()2()n()"()role="presentation">()(()−()1())()n()(()n()−()1())()!()x()−()2()n();()C.()(()−()1())()n()−()1()(()n()−()1())()!()x()n()"()role="presentation">()(()−()1())()n()−()1()(()n()−()1())()!()x()-n();()D.()(()−()1())()n()−()1()n()!()x()−()n()+()1()"()role="presentation">()(()−()1())()n()−()1()n()!()x()−()n()+()1().
- 设`\n`阶方阵`\A`满足`\|A| = 2`，则`\|A^TA| = ,|A^{ - 1}| = ,| A^ ** | = ,| (A^ ** )^ ** | = ,|(A^ ** )^{ - 1} + A| = ,| A^{ - 1}(A^ ** + A^{ - 1})A| = `分别等于（ ） A: \[4,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] B: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n + 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] C: \[4,\frac{1}{2},{2^{n + 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\] D: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\]
- 1．下列数列中，收敛但极限不为$1$的是 A: ${{(2+\frac{1}{n})}^{\frac{1}{n}}}$ B: ${{n}^{\frac{1}{n}}}$ C: $\frac{1}{{{n}^{2}}+1}+\frac{2}{{{n}^{2}}+2}+\cdots +\frac{n}{{{n}^{2}}+n}$ D: $\frac{{{(n!)}^{2}}}{{{n}^{n}}}$
- 顶点个数为n的有向图最多有（ ）条边。 A: n(n - 1)/2 B: n(n - 1) C: n(n + 1)/2 D: n(n + 1)