举一反三
- 下列程序的输出结果是( ) int main(void) { FILE *fp; int i,k,n; fp=fopen("data.dat","w+"); for(i=1;i<6;i++) { fprintf(fp,"%d",i); if(i%3==0) fprintf(fp,"\n"); } rewind(fp); fscanf(fp,"%d%d",&k,&n); printf("%d%d\n",k,n); fclose(fp); return 0;}
- 有以下程序:#include [stdio.h] main() { FILE *fp; int a[10]={1,2,3}, i, n; fp = fopen("d1.dat", "w"); for (i=0; i<3; i++) fprintf(fp, "%d", a[i]); fprintf(fp, "\n"); fclose(fp); fp = fopen("d1.dat", "r"); fscanf(fp, "%d", &n); fclose(fp); printf("%d\n", n); }程序的运行结果是()。[/i]
- 有以下程序:#include [stdio.h] main() { FILE *fp; int a[10]={1,2,3}, i, n; fp = fopen("d1.dat", "w"); for (i=0; i<3; i++) fprintf(fp, "%d", a[i]); fprintf(fp, "\n"); fclose(fp); fp = fopen("d1.dat", "r"); fscanf(fp, "%d", &n); fclose(fp); printf("%d\n", n); }程序的运行结果是()。[/i] A: 321 B: 12300 C: 1 D: 123
- 有以下程序:#include [stdio.h]main(){ FILE *fp; int a[10]={1,2,3}, i, n;fp = fopen("d1.dat", "w");for (i=0; i<3; i++) fprintf(fp, "%d", a[i]);fprintf(fp, "\n");fclose(fp);fp = fopen("d1.dat", "r");fscanf(fp, "%d", &n);fclose(fp);printf("%d\n", n);}程序的运行结果是()。[/i] A: 321 B: 12300 C: 1 D: 123
- 有以下程序:#include stdio.hmain(){ FILE *fp; int a[10]={1,2,3}, i, n;fp = fopen(d1.dat, w);for (i=0; i3; i++) fprintf(fp, %d, a[i]);fprintf(fp, \n);fclose(fp);fp = fopen(d1.dat, r);fscanf(fp, %d, n);fclose(fp);printf(%d\n, n);}程序的运行结果是()。[/i] A: 321 B: 12300 C: 1 D: 123
内容
- 0
下面程序的输出结果是________。#include<;stdio.h>;int main( ){ FILE *fp; int n,a[2]={65,66}; char ch; fp=fopen("d.dat","w"); fprintf(fp,"%d%d",a[0],a[1]); fclose(fp); fp=fopen("d.dat","r"); fscanf(fp,"%c",&ch); n=ch; while(n!=0){printf("%d",n%10);n=n/10;} fclose(fp); return 0;}
- 1
有以下程序: #include <stdio.h> main() { FILE*fp; int i,a[6] = {1,2,3,4,5,6},k; fp = fopen("data.dat", "w+b"); fwrite(&a[0],sizeof(int),1,fp); for(i=1; i<6; i++) { fseek(fp, 0L, 0); fread(&k, sizeof(int), 1, fp); fseek(fp, 0L, 0); a[i] +=k; fwrite(&a[i], sizeof(int), 1, fp); } rewind(fp); fread(&k, sizeof(int), 1, fp); fclose(fp); printf("%d\n",k); } 程序的运行结果是______。[/i][/i] A: 21 B: 6 C: 123456 D: 11
- 2
有以下程序#include "stdio.h"main(){ FILE *fp; int i, a[6] = {1,2,3,4,5,6}, k; fp = fopen("data.dat", "w+b"); fwrite(&a[0], sizeof(int), 1, fp); for (i=1; i<6; i++) { fseek(fp, 0L, 0); fwrite(&a[i], sizeof(int), 1, fp); } fseek(fp, 0L, 0); fread(&k, sizeof(int), 1, fp); fclose(fp); printf("%d\n", k);}程序运行后的输出结果是______。[/i] A: 6 B: 21 C: 123456 D: 654321
- 3
若有以下程序: #include <stdio.h> main( ) { FILE *fp; int i, a[6]={1,2,3,4,5,6},k; fp=fopen("data.dat","w+b"); for(i=0;i<6;i++) {fseek(fp,0L,0); fwrite(&a[5-i],sizeof(int),1,fp); } rewind(fp); fread(&k, sizeof(int),1,fp); fclose(fp); printf("%d",k); } 则程序的输出结果是______。 A: 6 B: 1 C: 123456 D: 21
- 4
以下程序运行后的输出结果是123456,请判断对和错 。#include <;stdio.h>;void main(){ FILE *fp; int x[6]={1,2,3,4,5,6},i;fp=fopen("test.dat","wb");fwrite(x,sizeof(int),3,fp);rewind(fp);fread(x,sizeof(int),3,fp);for(i=0;i<;6;i++)printf("%d",x[i]);printf("\n");fclose(fp);}[/i]