一元钱换为1、2、5分的硬币，有多少种兑换方法。public class ChangeMoney {public static void main(String[] args) {int count=0;for(int five=0;five<;=20;five++){for(int two=0;1;two++){int one=100-5*five-2*two;if(2){3 ;}}}System.out.println("一共有"+count+"种兑换方法");}}
举一反三
- 下列程序的运行结果是（）。 public class Test public static void main ( String [ ] args ) int count = 0 for( int i = 1 i < 5 i = 2) for( int j = 1 j< = 10 j = 3) count System .out .print (count ) _
- 写出下列程序的输出结果 public class Test { public static void main(String[] args) { Count myCount = new Count(); int times = 0; for(int i=0;i<100;i++) increment(myCount , times); System.out.println(“count is” + myCount.count); System.out.println(“time is”+ times); } public static void increment(Count c , int times) { c.count++; times++; } } class Count { public int count; Count(int c) { count =c; } Count() { count =1; } }
- class Count { public int count; public Count(int c) { count = c; } public Count() { count = 1; }}public class Test { public static void increment(Count c, int times) { c.count++; times++; } public static void main(String args[]) { Count myCount = new Count(); int times = 0; for (int i = 0; i A: myCount.count=4 times=0 B: myCount.count=3 times=0 C: myCount.count=4 times=1 D: myCount.count=3 times=1
- 代码中myCount.count的值为（A）?public class Test { public static void main(String[] args) { Count myCount = new Count(); int times = 0; for (int i=0; i<100; i++) increment(myCount, times); System.out.println("myCount.count = " + myCount.count); } public static void increment(Count c, int times) { c.count++; times++; }} class Count { int count; Count(int c) { count = c; } Count() { count = 1; }} A: 101 B: 100 C: 99 D: 98
- 请阅读下面的程序 Public class Test { public static void main(String[] args) { int a = 0; int b = 0; for (int i = 1; i <= 5; i++) {