以下程序的编译和运行结果为？ abstract class Base{ abstract public void myfunc(); public void another(){ System.out.println("Another method"); } } public class Abs extends Base{ public static void main(String argv[]){ Abs a = new Abs(); a.amethod(); } public void myfunc(){ System.out.println("My Func"); } public void amethod(){ myfunc(); } }
举一反三
- 以下程序的运行结果是______ abstract class class1{abstract void method1();}class class2 extends class1{public void method1(){ System.out.println("子类");}｝public class MainClass{public static void main(String args[]){class1 ac=new class2();ac.method1();}}
- 下列程序运行结果是( ) public class Demo { public static void main(String[] args) { Demo demo = new Demo(); demo.show(new Car() { public void run() { System.out.println("demo run"); } }); } public void show(Car c) { c.run(); } }abstract class Car { public void run() { System.out.println("car run..."); } }
- 请阅读下面的程序,写出运行结果,如果编译失败,写明失败原因。 abstract class Animal{ public final abstract void eat(); } class Cat extends Animal{ public void eat(){ System.out.println("cat...fish"); } } class CatDemo{ public static void main(String[] args){ Animal a = new Cat(); a.eat(); } }
- 如何能使程序调用Base类的构造方法输出"base constructor"; class Base{ Base(int i){ System.out.println("base constructor"); } Base(){ } } public class Sup extends Base{ public static void main(String argv[]){ Sup s= new Sup(); //One } Sup() { //Two } public void derived() { //Three } }
- 请阅读下面的程序,写出最终的结果: interface Inter { public void show(); } abstract class AbstractInter implements Inter { public void show() { System.out.println("AbstractInter show()"); } } class InterImpl extends AbstractInter { public void show() { System.out.println("InterImpl show()"); } } public class InterImplTest { public static void main(String[] args) { InterImpl i = new InterImpl(); i. show(); } }