• 2022-07-26
    以 [tex=0.5x1.0]qm+hGi0qngLh1B7HsENMPg==[/tex]作为广义坐标,其中杆的质量为 [tex=1.214x1.0]0+c/4hmvIG0q6AFNhqYE7A==[/tex] 建立 图 a 所示系统的微分方程.[img=510x240]179d6dd8760caf3.png[/img]
  • 以杆为研究对象,受力图如 图 b 所示,由动量矩定理有[tex=33.286x3.357]eFznE1XPYC7OCr3Ivh+k03i7FH15nzRr6b97nPUEQEYNe/z0nHB+kUAmu/AWhtLq+wapwKr4stFTwTXDqhYHzh+Ji1esA4S68+eAukdSw+s6thMW7W329Kh9INQPMOBlDbWHhC7DTOl6vvPeGuHUE4v0wf6+BY/pFeFOnwbiTLL/NUlc0F2zIOikfE3YCliM7GGK3KMbTyx2gxqEL2+MHpYFHFzDrfLAox9MtItOiN1H5/fJ+LlYo40iTLo+dZI3jdemttSdq7IRbthXd4EutZbHhG098ZlFBRkxUVELQpI=[/tex]由几何关系有[tex=11.357x2.786]FyhqrsImIzogfuiytvgacq7GBrRc9m32ZPB7xWnE6Wbq09D9dD4L/o28X+WX/hZUm8qylyKgGVG7rH2MMds+PpEcla0a28VeCtDqwnUpXP9mEqBw2LvtE+UM4T+6vdf9[/tex]代人方程,整理可得系统的微分方程为[tex=23.286x2.357]4SqUWdQKpbmwtaaNqaT4ppk0Z6tlzBpZr9U72TNwXFEnzwI80ZgEvohvEosPI4jAhUPzNMLfuLhs4SZ8WANf9VMxGGaMzSUexKhNjPPv7liGFTi5Gs9p0wUpF1Vz/C2FqG8xr2lUU9ADK/i7HEnhuY37WYKBDd2fF+xvB1ioT7dhTZIHMN+JoJiv8yPqbq/eh6OJiwDqIsfMdaCv/BTjvw==[/tex].[img=435x243]179d6e1759b8bfb.png[/img]

    内容

    • 0

      假定 list1 = [0.5 * x for x in range(0, 4)], list1 是什么?​‌​ A: [0, 1, 2, 3] B: [0, 1, 2, 3, 4] C: [0.0, 0.5, 1.0, 1.5] D: [0.0, 0.5, 1.0, 1.5, 2.0]

    • 1

      设X,Y为两个随机变量,且‏P{X ³0,Y ³ 0} = 3/7 , P{X ³ 0} = P{ Y ³ 0} = 4/7 ,‏则P{max(X, Y) ³ 0} = ( ).‏ A: 1/7 B: 3/7 C: 4/7 D: 5/7

    • 2

      过点(4,1,-1)且与直线[img=178x63]17e0aa0d7662054.png[/img]垂直的平面的方程为(). A: x - 4y + 7z - 1 = 0 B: x + 4y + 7z - 1 = 0 C: x - 4y + 7z + 7 = 0 D: x + 4y + 7z + 7 = 0

    • 3

      假设个体域D={1, 2, 3, 4, 5, 6},P(x):x是偶数,Q(x):x>0 ,R(x):x>6则[img=60x22]17e446cee76fe2e.png[/img]的真值为1;

    • 4

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}