试编程判断输入的正整数是否既是5又是7的整倍数。若是,则输出yes;否则输出no,下面程序段哪个能实现()
A: #includevoidmain(){inta;scanf("%d",a);if(a%5==0&&a%7==0)printf("yes");elseprintf("no");}
B: #includevoidmain(){inta;scanf("%d",&a);if(a%5==0&&a%7==0)printf("yes");elseprintf("no");}
C: #includevoidmain(){inta;scanf("%d",&a);if(a%5==0||a%7==0)printf("yes");elseprintf("no");}
D: #includevoidmain(){inta;scanf("%d",&a);if(a%5=0&&a%7=0)printf("yes");elseprintf("no");}
A: #includevoidmain(){inta;scanf("%d",a);if(a%5==0&&a%7==0)printf("yes");elseprintf("no");}
B: #includevoidmain(){inta;scanf("%d",&a);if(a%5==0&&a%7==0)printf("yes");elseprintf("no");}
C: #includevoidmain(){inta;scanf("%d",&a);if(a%5==0||a%7==0)printf("yes");elseprintf("no");}
D: #includevoidmain(){inta;scanf("%d",&a);if(a%5=0&&a%7=0)printf("yes");elseprintf("no");}
举一反三
- 下列程序判断输入的正整数是否既是5的倍数又是7的倍数。若是,则输出yes,否则输出no,请在程序中填空。#includemain(){intx;printf("请输入一个正整数:");scanf("%d",&x);if(&&x%7==0)printf("yes");elseprintf("no");}
- 执行下面程序的输出结果是()。main(){inta=5,b=0,c=0;if(a=a+b)printf("**** ");elseprintf("#### ");}
- 阅读下面的程序,该程序().main(){inta=5,b=0,c=0;if(a=b+c)printf("***\n");elseprintf("$$$\n");}
- 判断是否即是5又是7的整倍数编程判断输入的正整数是否既是5又是7的整倍数。若是，输出Yes，否则输出No。
- 下面程序的输出结果是_.#includevoidmain(){inta=-1,b=4,k;k=(++a<=0)&&(b–<=0);printf("%d,%d,%d\n",k,a,b);}