以下代码的输出结果?public class Test{static int...ge(int m){m+=2;}}
举一反三
- public class test { public static void main(String args[]) { int m=0; for ( int k=0;k<2;k++) method(m++); System.out.println(m); } public static void method(int m) { System.out.print(m); } }
- 以下代码的输出结果?public class Test{public sta...tring m){m=m+2;}}
- 下列代码的输出结果是（ ）interface Com{ int M=100; int on();}class A implements Com{ public int on(){ return Com.M; }}public class E{ public static void main(String args[]){ Com com=new A(); int m=com.on(); System.out.println(m); }}
- 给出下列代码，如何使成员变量m被方法fun()直接访问?class Test { private int m; public static void fun( ) { ... }} A．将 private int m 改为protected int m B．将private int m 改为public int m C．将private int m改为static int m D．将private int m改为int m
- 给出如下代码: class Test{ private int m(){ ...... } public static void fun() { ...... } } 如何使成员函数m() 被函数fun()直接访问 A: 将private int m() 改为protected int m() B: 将private int m() 改为 public int m() C: 将private int m() 改为 static int m() D: 将private int m() 改为 int m()