• 2021-04-14
    利用三角函数来化简符号表达式http://edu-image...cos(x)^2-sin(x)^2;F=
  • simplify,f,2*cos(x)^2-1

    内容

    • 0

      复数z=6i的三角形式为() A: cosπ/2+isinπ/2 B: cosπ/2-sinπ/2 C: sinπ/2+icosπ/2 D: sinπ/2-icosπ/2

    • 1

      以下表达式中,有两个的计算结果是相同的,请挑选出来 A: 1 / sqrt(sin(x) * sin(x) + cos(y) * cos(y)) B: sqrt(pow(sin(x), 2) + pow(cos(y), 2)) C: pow(sin(x) * sin(x) + cos(y) * cos(y), 0.5) D: pow(pow(sin(x), 2) + pow(cos(y), 2), 2)

    • 2

      求微分方程[img=634x60]17da653955cf9e7.png[/img]的特解。 ( ) A: sin(2*x)/3 - cos(x) - cos(x)/3 B: sin(2*x)/3 - cos(x) - sin(x)/3 C: cos(2*x)/3 - cos(x) - sin(x)/3 D: sin(2*x)/3 - sin(x) - sin(x)/3

    • 3

      求函数[img=107x38]17da6537b12a2e0.png[/img]的导数; ( ) A: 2*x*sin(1/x) - sin(1/x) B: 2xsin(1/x) - cos(1/x) C: 2*x*sin(1/x) - cos(1/x) D: 2*x*cos(1/x) - cos(1/x)

    • 4

      曲线积分$$\int_{(0,0}^{(x,y)}(2x\cos y-y^2\sin x)dx+(2y\cos x-x^2\sin y)dy=$$ A: $y^2\cos x+x^2\cos y$ B: $x^2\cos x+y^2\cos y$ C: $x^2\sin y+y^2\sin x$ D: $x^2\sin x+y^2\sin y$