下面代码的输出结果是
x2=1
for day in range(4,0,-1):
x1=(x2+1)*2
x2=x1
print(x1)
x2=1
for day in range(4,0,-1):
x1=(x2+1)*2
x2=x1
print(x1)
举一反三
- 求函数 f(x)=3*x1^2 + 2*x1*x2 + x2^2 − 4*x1 + 5*x2. 时,输入代码 >>fun = @(x)3*x(1)^2 + 2*x(1)*x(2) + x(2)^2 - 4*x(1) + 5*x(2); >>x0 = [1,1]; >>[x,fval] = fminunc(fun,x0); 其中fun的作用是:
- 求函数 f(x)=3*x1^2 + 2*x1*x2 + x2^2 − 4*x1 + 5*x2. 时,输入代码 >>fun = @(x)3*x(1)^2 + 2*x(1)*x(2) + x(2)^2 - 4*x(1) + 5*x(2); >>x0 = [1,1]; >>[x,fval] = fminunc(fun,x0); 到matlab上运行一下,得到的结果,x是:
- 下面代码的执行结果是( )[br][/br] x2 = 1 for i in range (4, 0, -1): x1 = ( x2 + 1 ) * 2 x2 = x1 print (x2)
- 下面代码的执行结果是( ) x2 = 1 for i in range (4, 0, -1): x1 = ( x2 + 1 ) * 2 x2 = x1 print (x2) A: 23 B: 94 C: 190 D: 46
- F(x1,x2,x3)= x 1 2 +2x 2 2 +5x 3 2 +2x 1 x 2 +2x 1 x 3 +6x 2 x 3 的标准形为()