网课答案LOGO
关注微信公众号《课帮忙》查题
关注微信公众号《课帮忙》查题
关注微信公众号《课帮忙》查题
关注微信公众号《课帮忙》查题
关注微信公众号《课帮忙》查题
关注微信公众号《课帮忙》查题
  • 2022-06-27
    求与下列各曲线相交成[tex=1.429x1.071]6wFjUg4eHIq46eioq8Pjcg==[/tex]角的曲线族：[tex=4.143x1.214]zS6dkWIziPDQVF1Jstha/A==[/tex];
    • 解：由方程得：[tex=10.286x3.357]fnpmC2J6JmQBLyo5NmGAz/kMVTwWceYy7CUhOQ9wUEa/LoEVTeqk3ZOQFS+VkHzBTpeQJAzOM5ftOnYYhwQgyhwKWtx1GWtkzsM+M39zI40=[/tex],消去a 有:[tex=4.571x2.429]dXga0r4SJTh9I2AwV7inFlY+/HOBCvt5e+GLauPZinc=[/tex],则所求等角轨线的微分方程为[tex=9.214x3.071]dXga0r4SJTh9I2AwV7inFmX2Rir/eKoRoC/zkaMBtdI383L+U46R1Ec3hfh7NhOrQparbIp//5QeBci1EcYp0NxQuTcjTHhTIyE9ZgxfN5GpfQ2WG+RPj2Is2Lc6dU73vjRmCNscU8mAWon6ZPb6B5Mnthe5ug6q8fIL9oeX5vg=[/tex],亦即[tex=7.786x1.357]a93W3bkgQ8X+W3/5ATWtLUhoar9UvGpFg0mIQAXA9mE=[/tex],所以所求等角轨线族为[tex=19.429x2.786]3GfiZ2O+m35DC9xA0YxzjsvAvoNyLl2mSZZNk3F72rd42uTHqI95kZRymoOvjKPpVS7qBwdGw0/xdxG/NFemFThJNxg0XcM8krlef+z9WWygtulOqSCIdtp7+gXb/2cpw+Lk6D9TMtXgjNvw53m/hHNFJ91GU3QVb7rsbAupddw=[/tex]
    公众号
    广告招租

    举一反三

    内容

    • 0

      求下列各曲线族的正交轨线族：[tex=3.214x1.429]52BNqejfXy656ai6MPZ1HQ==[/tex];

    • 1

      求下列各曲线族的正交轨线族：[tex=3.857x1.429]VjKK0zi64WcnKcnoL9RcPQ==[/tex]

    • 2

      求下列各曲线族的正交轨线族：[tex=2.286x1.0]sdiORd21alyeXynfkZsstw==[/tex];

    • 3

      平刺是指针刺与皮肤所成的角度为( ) 未知类型：{'options': ['[tex=1.929x1.071]EQVn6xTTVMeHKRmyIA8ktg==[/tex]', '[tex=1.429x1.071]HrADEgZoqo90D/eowIUddQ==[/tex]', '[tex=1.429x1.071]6wFjUg4eHIq46eioq8Pjcg==[/tex]', '[tex=1.429x1.071]Rgqj8bHi4xyxE+qK+DyGug==[/tex]', '[tex=1.429x1.071]3taJkn2+7hmo0Oj13QzJbQ==[/tex]'], 'type': 102}

    • 4

      求下列各曲线族的正交轨线族：[tex=4.786x1.429]rQ0cSvXcV9twzEOC6TY0TFJFP/Wb8q7FsywHOTDjoyQ=[/tex];