我国2M复用成AUG的骤是()
A: C-12->VC-12->TU-12->TUG-2->VC-3->AU-4->AUG
B: C-12->VC-12->TU-12->VC2->TUG-2->TUG-3->AU-4->AUG
C: C-12->VC-12->TU-12->TUG-2->TUG-3->VC-4->AU-4->AUG
D: C-12->VC-12-->TU-12->TUG-2->VC-3->TUG-3->AU-4->AUG
A: C-12->VC-12->TU-12->TUG-2->VC-3->AU-4->AUG
B: C-12->VC-12->TU-12->VC2->TUG-2->TUG-3->AU-4->AUG
C: C-12->VC-12->TU-12->TUG-2->TUG-3->VC-4->AU-4->AUG
D: C-12->VC-12-->TU-12->TUG-2->VC-3->TUG-3->AU-4->AUG
C
举一反三
- SDH的基本复用单元包括C、VC、()、TUG、AU和AUG。 A: C B: VC C: TU D: AU
- 函数factor(sym(12))的值是( )。 A: '12' B: 12 C: [3, 4] D: [ 2, 2, 3]
- 如下代码的运行结果为:( ) A: array([[-10, -8, -6, -4, -2],[ 0, 2, 4, 6, 8]]) B: array([[ 1, 2, 3, 4, 5],[ 6, 7, 8, 9, 10]]) C: array([[-11, -10, -9, -8, -7],[ -6, -5, -4, -3, -2]]) D: array([[12, 12, 12, 12, 12],[12, 12, 12, 12, 12]])
- φ(12)=φ(3*4)=φ(2*6)=φ(3)*φ(4)=φ(2)*φ(6
- VC全称为,TU全称为;AU全称为
内容
- 0
中缀表达式23+((12*3-2)/4+34*5/7)+108/9对应的后缀表达式为( )。 A: 23 12 + 3 * 2 – 4 / 34 5 * 7 / + 108 9 / + B: 23 12 3 * 2 4 – / 34 5 * 7 / + + 108 9 / + C: 23 12 3 * 2 – 4 / 34 5 * 7 / + 108 9 / + + D: 23 12 3 * 2 – 4 / 34 5 * 7 / + + 108 9 / +
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下面代码的执行 结果是print(2**2*3) print(2*2**3) A: 12 16 B: 16 12 C: 16 16 D: 12 12
- 2
Which statement below initializes array items to contain 3 rows and 2 columns? ( ) A: int[][] items = {{2, 4}, {6, 8}, {10, 12}}; B: int[][] items = {{2, 6, 10}, {4, 8, 12}}; C: int[][] items = {2, 4}, {6, 8}, {10, 12}; D: int[][] items = {2, 6, 10}, {4, 8, 12};
- 3
int a[12]={1, 4, 7, 10, 2, 5, 8, 11, 3, 6, 9, 12 };
- 4
构造一个模12同步计数器,至少需要( )个触发器。? 3|2|12|4