设数列[tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex] 收敛,证明该数列必有最大项或最小项.
举一反三
- 数列[tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex], 收敛还是发散，对于收敛数列，通过观察得出数列的极限：[tex=5.286x2.643]xKdhHwdqRKSewu3ObrxAC3WizSeE3twciGNEQIZM2cU=[/tex]
- 数列[tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex], 收敛还是发散，对于收敛数列，通过观察得出数列的极限：[tex=5.357x2.643]2HOhxEdt8BK5aL94AJddc0SjRnQ2eFWE3Y5xrCdfPrA=[/tex]
- 数列[tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex], 收敛还是发散，对于收敛数列，通过观察得出数列的极限：[tex=6.929x2.214]aFon6MejDGxOD6fY3vgLBbFXssMAoRHQ5mbFf39mpeQmqXSaUYuicJBXolfWJKD8[/tex]
- 数列[tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex], 收敛还是发散，对于收敛数列，通过观察得出数列的极限：[tex=4.929x1.357]nIRQmPG5H+oXUeobMrN9Q5+ml9EecB8wS61iAkDzsDE=[/tex]
- 设数列 [tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex] 为 [tex=23.214x3.429]a1YRyGaFgFaGLcsbr8maqGm8cLhDPF3o3MWtj74uBuSJi2ZWUMslO09FxtgkgkutXSueCpqx17H/p9Vkd7+TTcviTp0nKDbwgiunyFTo7trs1HHLHgMEIUuA1gjz3OHuH8Ghx65QNeTpRvgF7P1vjQ==[/tex]试证 [tex=2.0x1.357]CjCvAldACdhCbOUJYZLY+0nRBLhCQFA+2tCS8je5CxI=[/tex] 收敛，并求它的极限。