解 显然函数[tex=3.786x1.286]a7syGVnHJ8vV4xZ+ta96jg==[/tex]在[tex=2.429x1.286]S1HxAiM3J26aK6+SDag+4g==[/tex]连续，因此函数[tex=3.786x1.286]a7syGVnHJ8vV4xZ+ta96jg==[/tex]在[tex=2.429x1.286]S1HxAiM3J26aK6+SDag+4g==[/tex]可积。 令[tex=2.643x2.0]mlVWpGDoz8IYERZHMA/3sDkmXBlqg6zh3Zl6JPfMY5E=[/tex]， 将[tex=2.429x1.286]S1HxAiM3J26aK6+SDag+4g==[/tex]等分成[tex=0.643x1.286]ZsZs11iKEvfmzDIurZth8g==[/tex]个小区间，分点的坐标依次为[tex=11.286x1.286]fUp03NUn2EFqZAPzQvaDTA6SGDU18kRQXWyxRKPRqjY=[/tex] 。取[tex=0.857x1.286]XyXCZt1Q+/n4OruiL7XuYQ==[/tex]是小区间[tex=6.071x1.286]45/VDQ7yYg5ywR+7eTKb+RMN3ywnuWAltMpM2I6yepU=[/tex]的右端点， 即[tex=3.357x1.286]7Kl+E/7UhEAWw+OTcTFSz5upH9u6vQgN4gO7tGMnItw=[/tex]。 于是[tex=18.714x6.357]SMCiZCjCLMG8LLJWa9iOzGjqciB6z2ZOyLu2uhr3Im8Uv9EthsGsX3jzbawLZBHKlM1E7/OkATDbGKKLdhLs6TbgWi8xcup3gBzmEYkK6Yxw5WdF2nVUlsBO/mnYSUZwSPPVzhf1lvEjWH5Pg18x3iT8efyJmy4LOjWcgjCqgHl9gi8xV5IP8l6ECZyiHPHjJwx2oAQ/iE24109i/aBbSXRggQb/lxVOYkYbY6Gu3ROB5u/kT05Czfz8NOuYi9k5/XphDEoFlxm3ZlyUqgvmhHFw3Vlpgt9JjNJiefblqxAzGPrqZ8a0QH5f4dXZoN8dDOENxz8gtTfusCz/iCt4qrjAs6rkNhX0D0n84RDqHyApauNXnxuVbrV7W5icHAdEJnnb5EYfi0PBazNTFhvXHg==[/tex]