以下程序的输出结果是().structst{intx;int*y;}*p;intdt[4]={10,20,30,40};structstaa[4]={50,
举一反三
- 下面程序的输出结果为()structst{intx;int*y;}*p;intdt[4]={10,20,30,40};structstaa[4]={50,&dt[0],60,&dt[1],70,&dt[2],80,&dt[3]};main(){p=aa;printf("%d",++p->x);printf("%d",(++p)->x);printf("%d",++(*p->y));}
- 以下程序的输出是()。structst{intx;int*y;}*p;intdt[4]={10,20,30,40};structstaa[4]={50,&dt[0],60,&dt[0],60,&dt[0],60,&dt[0]};main(){p=aa; printf("%d\n",++(p->x)); }? 60|10|11|51
- 以下程序的输出结果是().structst{intx;int*y;}*p;int...f("%d\n",++(p->x));}
- 下面程序的输出结果为( )? struct ??st? ? ? ? ?int x? ? ? ? ? int y? p? int ?dt[4]=10,20,30,40? struct ? st ?aa[4]= 50,
- 下面程序的输出结果为()structst{intx;int*y;}*p;intd...("%d\n",++(*p->y));}