• 2021-04-14
    From the dialogue, Jack worries about _______.f025e0f66cfad8510d62b30123c56922.png
  • what to wear

    内容

    • 0

      设f(x)=(1+x)cosx,欲使f(x)在x=0处连续,则f(0)定义为()。 A: f(0)=0 B: f(0)=e-1 C: f(0)=1 D: f(0)=e

    • 1

      Listen to the dialogue about working from home. Q: According to the woman, why does working from home make sense?

    • 2

      设f(x)=x2+bx+x满足关系式f(1+x)=f(1-x),则下述结论中,正确的是( ). A: f(0)>f(1)>f(3) B: f(1)>f(0)>f(3) C: f(3)>f(1)>f(0) D: f(3)>f(0)>f(1) E: f(1)>f(3)>f(0)

    • 3

      下列哪个选项是函数 f:N→Z,f(n)=n² 的递归定义? A: f(n)=nf(n-1)+1,f(0)=0 B: f(n)=f(n-1)+(2n-1),f(0)=0 C: f(n)=f(n-1)²,f(0)=0 D: f(n)=f(n-1)+(2n+1),f(0)=0 E: f(n)=2f(n-1)+2

    • 4

      设在[0,1]上f""(x)>0,则f"(0)f"(1),f(1)-f(0)或f(0)-f(1)的大小顺序是() A: f"(1)>f"(0)>f(1)-f(0)。 B: f"(1)>f(1)-f(0)>f"(0)。 C: f(1)-f(0)>f"(1)>f"(0)。 D: f"(1)>f(0)-f(1)>f"(0)。