• 2021-04-14
    给定一个Servlet的代码片段如下:

    Public void doGet(HttpServletRequest request,HttpServletResponse response)

    throws ServletException,IOException{

    ______

    out.println("hi kitty! ");

    out.close();

    }

    运行Servlet时输出:hi kitty!

    则应在此Servlet下划线处填充如下代码
  • 举一反三