设u=cos(xy),则du=().
举一反三
- 设u=cos(xy),则du=( ).? cos(xy)(ydx+xdy)|-sin(xy)(ydx+xdy)|sin(xy)(ydx+xdy)|-cos(xy)(ydx+xdy)
- 设f(u)连续，且du(x，y)=f(xy)(ydx+xdy)，则u(x，y)=______．
- 设\(z = {e^u}\sin v,\;u = xy,\;v = x + y\)，则\( { { \partial z} \over {\partial y}}=\)( ) A: \(x{e^{xy}}\sin \left( {x + y} \right) + {e^{xy}}\cos \left( {x + y} \right)\) B: \(x{e^{xy}}\sin \left( {x + y} \right) \) C: \( {e^{xy}}\cos \left( {x + y} \right)\) D: \(x{e^{xy}}\sin \left( {x + y} \right) - {e^{xy}}\cos \left( {x + y} \right)\)
- 设\(z = xy{e^{\sin xy}}\)，则\({z'_y} = \)（ ）。 A: \(x{e^{\sin xy}}\left( {1 + xy\cos xy} \right)\) B: \(y{e^{\sin xy}}\left( {1 + xy\cos xy} \right)\) C: \(x{e^{\sin xy}}\left( {1 + y\cos xy} \right)\) D: \(x{e^{\sin xy}}\left( {1 - xy\cos xy} \right)\)
- 设函数u=x2+y2-exy，则全微分du=______．