举一反三
- 以下代码的显示结果是什么? data=[[[1,2],[3,4]],[[5,6],[7,8]]] print(data[1][0][0]) A: 1 B: 2 C: 4 D: 5 E: 6
- 下面程序的输出是。data=[[0]*3] *3data[2][2]=7print(data[0][2])
- 写出下面程序的输出结果:d1 = {} d1[2] = 10 d1['2'] = 20 d2 = {} d2[2] = d1 d2['2'] = d2 print d2['2']['2']['2']['2'][2][2]
- ls=[ [1,2,3,4],['a','b','c','d'],['列','表'] ][br][/br] 请写出结果: ls[0] (1) ls[0][0] (2) ls[1][0:2] (3)
- 已知列表m=[[1,2],[3,4]],有列表a=[[row[i] for row in m] for i in range(2)],则a[0][1]是[/i]
内容
- 0
下面程序运行结果为(______ )data = [2, 3, 5, 8, 13]new_data = [ ]for i in range(20, 1, -3): if i not in data: new_data.append(i)print(new_data)
- 1
以下程序的输出结果是: ls=[[1,2], 'python', [[3,4,'A'],5],[0,7]] print(ls[2][1]) A: 'A' B: p C: 3 D: 5
- 2
若int a[][]={{123,345,60},{34,56},{34,56}},则a[2][1]+a[0][2]= ______
- 3
已知 vec = [[1,2], [3,4]],则表达式 [[row[i] for row in vec] for i in range(len(vec[0]))]的值为______________()_________。[/i] A: [1, 2, 3, 4] B: [[1, 2, 3], 4] C: [[1, 3], [2, 4]] D: [1, 2, [3, 4]]
- 4
已知 vec=[[1,2],[3,4]],则表达式[[row[i] for row in vec] for i in range(len(vec[0]))]的值为( )[/i]