假设有模板定义如下:
A: templatefloatMin(Tm1,Tm2){return(m1}
B: templateT1Min(T1m1,T2m2){return(m1}
C: templateT1Min(T1a[],T2n){T1minnum=a[0];for(inti=0;iif(minnum>a[i])minnum=a[i];returnminnum;}
D: templateTMin(Tm1,Tm2,Tm3){Ttemp=Min(m1,m2);returnMin(temp,m3);}
A: templatefloatMin(Tm1,Tm2){return(m1}
B: templateT1Min(T1m1,T2m2){return(m1}
C: templateT1Min(T1a[],T2n){T1minnum=a[0];for(inti=0;iif(minnum>a[i])minnum=a[i];returnminnum;}
D: templateTMin(Tm1,Tm2,Tm3){Ttemp=Min(m1,m2);returnMin(temp,m3);}
举一反三
- 假设有模板定义如下:template T Min(T m1, T m2 ){return (m1 A: template float Min(T m1, T m2 ){return (m1 B: template T1 Min(T1 a[ ], T2 n ){T1 minnum=a[0] ;for (int i=0 ;ia[i]) minnum=a[i];return minnum;} C: template T1 Min(T1 m1, T2 m2 ){return (m1 D: template T Min(T m1, T m2, T m3 ){T temp=Min(m1,m2) ;return Min(temp , m3) ;}
- 【单选题】那种波段组合是真彩色()。 A. R,G,B => TM1,TM2,TM3 B. R,G,B => TM2, TM 3, TM 1 C. R,G,B => TM 4, TM 3, TM 2 D. R,G,B => TM 3, TM 2, TM 1
- 标准斜齿圆柱齿轮外啮合的正确啮合条件是()。 A: m1=m2=mn,α1=α2=αn,β1=-β2 B: m1=m2=m ,α1=α2=α,h1=h2 C: m1=m2=mn,α1=α2=αn,β1=β2 D: m1=m2=m ,α1=α2=α,β1=β2
- 。 (1)A::A(int m) { this->m = m; } (2)A::A(int m) { this.m = m; } (3)A A::T() { m++; return *this; } (4)A A::T() { m++; return this; } (5)A A::T() { m++; return T; }
- 在下列六组量子数中,正确的是① n=3,l= 1,m=-1 ② n = 3,l= 0,m = 0③ n = 2,l= 2 ,m=-1 ④ n = 2, l = 1 ,m = 0 ⑤ n = 2,l = 0,m =-1 ⑥ n= 2,l = 3 , m= 2 A: (1),(2),(4) B: (2),(4),(6) C: (1),(2),(3) D: (1),(3),(5)