• 2022-11-03
    图示简支梁,试求其截面[tex=0.857x1.0]PvQ1rNj9zmhWbdNmDhnQhA==[/tex]上 [tex=4.214x1.214]xQ9fFZ1Y5o7HpwFqIi8oVJuFw3UyrPLdWT5bb0m/p8o=[/tex]五点处的正应力。[img=372x165]179d1cce4bf0b2a.png[/img]
  • 解 (1) 计算惯性矩[tex=15.714x2.5]Cg6deIwoCcuhY5NH5W05H+Ew8K7WZUh0CY5o2BZvaZgxdt7WKUO7xHECFO6bkgj7sniG7TM1OHja2bSdi8TBJrwZDrBi97fKSneN9RU3HzRk4wSpeSh3w+4wSvUz+BQ/[/tex](2) 计算弯矩[tex=10.571x2.429]GTf/mrwTe7C0qXpq8F/pj/i+BYGxDwxqojWHQ8WBsTKaGdnZW1+zmety0ojzaCp+7iY2KQkAlvT7XPTABfrFKw==[/tex](3) 计算各点正应力[tex=22.429x2.786]E52UbpHico/Q5XgAEyy+Az93bjMCaAjENxL4/DGOXcLi/pcW9umQG7RfAWgW40xXlp0aUArwpqayMIZfkS4g03yqoCzpaNUujOKJ4eUNshMHelweRsI6mqEDHGDAO06YzNU1OQwxXvSVl4gZpoA3kanPIVLfGQeQfupE2ykStV9YM1PW2YE3BebCfBIm+wUyjkcCz7uolaME7l27FolHYQ==[/tex](压 )[tex=24.786x2.786]2gshxUdYeenSkG5Zdx9GpXiWTTkMKiPYpGA9SnowjzBaeyqcE3cgvSrUmOHhk2obMk43HGXrjtSUCoY19ecCib5txYh1VeX1IJ4aWSDVVIeNctX9psILEtHlpmPA+w11HlpF5cww+rO97SimCDWgSKlzGC55gIY/Oj+NS1uH3p52AWqGsSpX9c2LEsN3Ri2UGrGk1ZesdMmNIkh5YCV1fg==[/tex](压)[tex=5.857x2.571]+n03kxPwDZeRL8OgMIZtTifsrDBwSl146el9buO9fFl5ORdebXeN4OgfDOVT3uwS[/tex][tex=22.5x2.643]pwAhYvxIHZRNtHGQHFKaLl6cR8hCS5CoNP9m/hUHC1AVQZJbZgvkMcXguhEH0NFTtA6QGdHewGwUVHHqE/epj//XXwd5uLQXuxC7hjAByRCP2PE1LmX9l1ok+VOwTLmS8NRJDF0HDhI1DNGysHSQdQAHD4e/HnYan5ZPyGnUvGp3+SeYfSFId01QIwI7x7uiPHMZ8NzT3oSfy2os2uKPSA==[/tex](拉)[tex=19.857x2.643]ZvAu4vBdyZwM4i7hhOhckoN11noXFXEVFlmJKTg25PIMliChxTWuZrTqGC4ke/VHwDhu1L0Ufz7LR/e5cUyeggvzVXIMkT01HSlNAdChUsbSrk1TkQ/OLkg45H076seZgnmmii6Sj7wYMDQQRlZGVxLEJ7b81Rk1OmkF7KmCdy68UFk2rWPZd3XOgKDYXZLh[/tex](拉)[img=165x170]179d1cf32aa2981.png[/img]

    内容

    • 0

      下面是图的拓扑排序的是?(多选)[img=340x240]1802faef6ebcc2a.png[/img] A: 2 8 0 7 1 3 5 6 4 9 10 11 12 B: 2 8 7 0 6 9 11 12 10 1 3 5 4 C: 8 2 7 3 0 6 1 5 4 9 10 11 12 D: 8 2 7 0 6 9 10 11 12 1 3 5 4

    • 1

      有代码片段:function f(y) {var x=y*y;return x;} for(var x=0;x< 5;x++) {y=f(x);document.writeln(y);}输出结果是( )。 A: 0 1 2 3 4 B: 0 1 4 9 16 C: 0 1 4 9 16 25 D: 0 1 2 3 4 5

    • 2

      以下程序的输出结果是() main( ) { int i , x[3][3]={9 , 8 , 7 , 6 , 5 , 4 , 3 , 2 , 1} , *p=&x[1][1] ; for(i=0 ; i<4 ; i+=2) printf("%d " , p[i]) ;

    • 3

      【单选题】请用地点定桩法在4分钟内记忆数字。 4 0 1 3 6 3 5 1 9 8 8 9 7 2 9 3 0 9 5 3 1 7 7 5 2 3 3 0 5 0 1 4 1 3 8 3 5 7 9 7 (5.0分) A. 已背 B. 未背

    • 4

      【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=