利用换元法求积分[tex=4.071x2.643]i0B0Y2rSCytpWSNDGYxuv6hi25ojS4+FhORJ8Adve4s=[/tex].
举一反三
- 用换元法计算下列积分：[tex=4.071x2.643]083DcokPjtmQ5ozbI21f8pvUEWG/dDiYrGXvpcvKCag=[/tex]
- 用换元法求不定积分：[tex=4.071x2.643]DmpYY89t9qN2k2xgilglLym1nMcax0Fw9EnkcsJw0mg=[/tex]
- set1 = {x for x in range(10) if x%2==0} print(set1) 以上代码的运行结果为？ A: {0, 2, 4, 6} B: {2, 4, 6, 8} C: {0, 2, 4, 6, 8} D: {4, 6, 8}
- 以下代码的输出结果是（）for i in range(0,10,2): print(i,end="") A: 0 2 4 6 8 B: 2 4 6 8 C: 0 2 4 6 8 10 D: 2 4 6 8 10
- 利用换元法求积分[tex=5.643x2.643]1g7y0RDxfkhDe0WwlUQGsgvs5wAK7NvFEeyGrUTTUWE=[/tex].