设指针变量p指向双向链表中结点A,指针变量s指向被插入的结点X,则在结点A的后面插入结点X的操作序列为()。
A: p->next=s;s->prior=p;p->next->prior=s;s->next=p->next;
B: s->prior=p;s->next=p->next;p->next=s;p->next->prior=s;
C: p->next=s;p->next->prior=s;s->prior=p;s->next=p->next;
D: s->prior=p;s->next=p->next;p->next->prior=s;p->next=s;
A: p->next=s;s->prior=p;p->next->prior=s;s->next=p->next;
B: s->prior=p;s->next=p->next;p->next=s;p->next->prior=s;
C: p->next=s;p->next->prior=s;s->prior=p;s->next=p->next;
D: s->prior=p;s->next=p->next;p->next->prior=s;p->next=s;
举一反三
- 在循环双链表的p所指结点后插入s所指结点的操作是（ ）。 A: s-＞prior=p; s-＞next=p-＞next; p-＞next=s; p-＞next-＞prior=s; B: p-＞next=s; p-＞next-＞prior=s; s-＞prior=p; s-＞next=p-＞next; C: p-＞next=s; s-＞prior=p; p-＞next-＞prior=s; s-＞next=p-＞next; D: s-＞prior=p; s-＞next=p-＞next; p-＞next-＞prior=s; p-＞next=s;
- 在循环双链表的P所指节点之后插入s所指节点的操作是( ) A: p->next=s; s->prior=p; p->next->prior=s; s->next=p->next; B: p->next=s; p->next->prior=s; s->prior=p; s->next=p->next; C: s->prior=p; s->next=p->next; p->next=s; p->next->prior=s; D: s->prior=p; s->next=p->next; p->next=s;p->next->prior=s;
- 在循环双链表的p所指的结点之前插入s所指结点的操作是 （ ） A: p->;prior = s；s->;next = p；p->;prior->;next = s；s->;prior = p->;prior； B: p->;prior = s；p->;prior->;next = s；s->;next = p；s->;prior = p->;prior； C: s->;next = p；s->;prior = p->;prior；p->;prior = s；p->;prior->;next = s； D: s->;next = p；s->;prior = p->;prior；p->;prior->;next = s；p->;prior = s；
- 在循环双链表的p所指结点之后插入s结点的操作是（ ） A: p->next=s; s->pre=p; p->next->pre=s; s->next=p->next; B: p->next=s; p->next->pre=s; s->pre=p; s->next=p->next; C: s->pre=p; s->next=p->next; p->next->pre=s; p->next=s; D: s->pre=p; s->next=p->next; p->next=s; p->next->pre=s;
- 在一个双链表中,在* $p$ 结点之后插入一个结点*s 的操作是[input=type:blank,size:4][/input]。 A: s-> prior =p ; p->n e x t=s ; p-> next -> prior =s ; s->n e x t=p-> next s -> next = p -> next ； B: p -> next -> prior = s ; p -> next = s ; s \rightarrow> prior = p C: p -> next = s ; s \rightarrow> prior = p ; s -> next = p -> next ; p -> next -> prior = s ; D: p -> next -> prior = s ; s -> next = p -> next ; s \rightarrow prior = p ; p -> next = s