Afinancialadvisorgathersthefollowinginformationaboutanewclient:
·Theclientisasuccessfuleconomicsprofessoratamajoruniversity
·Theclientplanstoworkfulltimeforsevenyearsandthenwillworkparttimefor3yearsbeforeretiring
·Theclientownstwohomesanddoesnothaveanyoutstandingdebt
·Theclienthasaccumulatedretirementsavingsofapproximately$2millionthroughtheiremployer’sretirementplanandwillhaveanticipatedretirementspendingneedsof$60,000peryear
·Theclientreadsnumerousfinancialpublicationsandfollowsmarketsclosely
·Whileconcernedaboutthecurrenthealthoftheglobaleconomy,theclientmaintainsthatheisalong-terminvestor.
Basedontheaboveinformation,whichofthefollowingbestdescribesthisclient?
A: lowabilitytotakerisk,butahighwillingnesstotakerisk
B: highabilitytotakerisk,butalowwillingnesstotakerisk
C: highabilitytotakeriskandahighwillingnesstotakerisk
·Theclientisasuccessfuleconomicsprofessoratamajoruniversity
·Theclientplanstoworkfulltimeforsevenyearsandthenwillworkparttimefor3yearsbeforeretiring
·Theclientownstwohomesanddoesnothaveanyoutstandingdebt
·Theclienthasaccumulatedretirementsavingsofapproximately$2millionthroughtheiremployer’sretirementplanandwillhaveanticipatedretirementspendingneedsof$60,000peryear
·Theclientreadsnumerousfinancialpublicationsandfollowsmarketsclosely
·Whileconcernedaboutthecurrenthealthoftheglobaleconomy,theclientmaintainsthatheisalong-terminvestor.
Basedontheaboveinformation,whichofthefollowingbestdescribesthisclient?
A: lowabilitytotakerisk,butahighwillingnesstotakerisk
B: highabilitytotakerisk,butalowwillingnesstotakerisk
C: highabilitytotakeriskandahighwillingnesstotakerisk
举一反三
- 有三个关系R、S和T如下，则由关系R和S得到关系T的操作是（ ） [br][/br] R [br][/br] [br][/br] [br][/br] S [br][/br] [br][/br] [br][/br] T [br][/br] A B C [br][/br] A B C [br][/br] A B C a 1 2 [br][/br] a 1 2 [br][/br] b 2 1 b 2 1 [br][/br] d 2 1 [br][/br] c 3 1 c 3 1 A: 差 B: 自然连接 C: 交 D: 并
- 已知4个矩阵连乘，A1=M5,3，A2=M3,1，A3=M1,4，A4=M4,6，求矩阵链积A1×A2×A3×A4的最佳求积顺序。（要求：给出计算步骤） 请填写乘积次数 [br][/br] 1 2 3 4 1 0 [br][/br] [br][/br] [br][/br] 2 [br][/br] 0 [br][/br] [br][/br] 3 [br][/br] [br][/br] 0 [br][/br] 4 [br][/br] [br][/br] [br][/br] 0 请填写添加括号的位置 [br][/br] 1 2 3 4 1 0 [br][/br] [br][/br] [br][/br] 2 [br][/br] 0 [br][/br] [br][/br] 3 [br][/br] [br][/br] 0 [br][/br] 4 [br][/br] [br][/br] [br][/br] 0
- 第2空:[br][/br]12[br][/br] 第3空:[br][/br]2[br][/br] 第4空:[br][/br]1
- 有以下程序：[br][/br]#include <stdio.h>[br][/br]main（）[br][/br]{ int a=2，b=2，c=2；[br][/br]printf（＂%d＼n＂，a／b&c）；[br][/br]}[br][/br]程序运行后的输出结果是（ ）。[br][/br] A: 0 B: 1 C: 2 D: 3
- 下面程序的输出结果是[br][/br] iX=3[br][/br] iX>3[br][/br]____ 。[br][/br]#include "stdio.h"[br][/br]main()[br][/br]{int iX=3;[br][/br] switch(iX)[br][/br] { case 1:[br][/br] case 2: printf("iX[3\n");<br] case 3: printf("iX=3\n");[br][/br] case 4:[br][/br] case 5: printf("iX>3\n");[br][/br] default: printf("iX unknow\n");[br][/br] }[br][/br]}