point to
A: 表明
B: 对着
C: 针对
D: 寻找
A: 表明
B: 对着
C: 针对
D: 寻找
A
举一反三
- point out A: 指出 B: 指向 C: 针对 D: 指路
- POP广告是( )。 A: point of product B: point of promotion C: point of purchasing D: point of point
- As we were ( ) giving up hope, a letter arrived. A: in the point of B: to the point of C: on the point of D: for the point of
- 语句inta=10,*point=&a;()其值不为地址。 A: point B: &a C: &point D: *point
- 寻找顾客主要指针对新的可能的准顾客的寻找。
内容
- 0
Confidence is good ________, but you cannot be proud. A: up in a point B: up to a point C: up on a point D: up of a point
- 1
语句int a=10,*point=&a;( )的值不是地址。 A: point B: &a C: &point D: *point
- 2
题 (1.0分) 题号:705 难度:中 第1章[br][/br]若有语句int *point,a=4;和 point=&a;下面均代表地址的一组选项是()。 A: a,point,*&a B: &*a,&a,*point C: *&point,*point,&a D: &a,&*point,point
- 3
下列代码中: class Point{ int x,y; public: Point(int a, int b=0); //① Point(Point &aPoint); //②Point(Point *p); //③ 默认的构造函数是 A: ① B: ② C: ③ D: 没有
- 4
Your question is ____________. A: beside the point B: point of view C: to point