• 2022-06-06
    作出线性函数的图像:[br][/br][tex=17.071x2.143]RXipo3kSHkCsotovDrA+Xy1X/mFfZU5yDzC3uHYBEiOyZha9oj2Xz25xWg/JEAQsportl+M64Z54KueuH87Bjw==[/tex]
  • 解如图1.15所示.[br][/br][img=314x273]178d8ac0c08e241.png[/img]

    内容

    • 0

      作出下列分式线性函数的图像(双曲线):[br][/br][tex=2.286x2.357]WZ1eGuQpHcRKWyEd/Sly/Q==[/tex]

    • 1

      判断下列逻辑运算说法是否正确。(1)若X+Y=X+Z,则Y=Z;()(2)若XY=XZ,则Y=Z;()(3)若X⊕Y=X⊕Z,则Y=Z;()

    • 2

      执行以下语句的结果:dict1={"x":1,"y":2,"z":3}dict2={"x":4,"a":5}dict1.update(dict2) A: {"x":1,"y":2,"z":3,"x":4,"a":5} B: {"x":4,"a":5,"x":1,"y":2,"z":3} C: 有重复项,结果有误! D: {"x":4,"y":2,"z":3,"a":5}

    • 3

      设\(z = u{e^v}\),\(u = {x^2} + {y^2}\),\(v = xy\),则\( { { \partial z} \over {\partial y}}=\)( )。 A: \({e^{xy}}({x}y^2 + {x^3} + 2y)\) B: \({e^{xy}}({x^2}y + {x^3} + 2y)\) C: \({e^{xy}}({x}y^2 + {x^3} + 2x)\) D: \({e^{xy}}({x}y+ {x^3} + 2y)\)

    • 4

      设\(z = z\left( {x,y} \right)\)是由方程\({z^3}{\rm{ + }}3xyz - 3\sin xy = 1\)确定的隐函数,则\( { { \partial z} \over {\partial y}}=\)( ) A: \( { { y\left( {\cos xy - z} \right)} \over { { z^2} + xy}}\) B: \( { { y\left( {z - \cos xy} \right)} \over { { z^2} + xy}}\) C: \( { { x\left( {\cos xy - z} \right)} \over { { z^2} + xy}}\) D: \( { { x\left( {z - \cos xy} \right)} \over { { z^2} + xy}}\)