• 2022-06-06
    给定[tex=18.857x1.357]ngpG1B8u7E4WNR8GhTG0jUd/uf8Uck78j9eNn4RLNcGCIFezj5XfOz7e0A0SCleB0Kmhynl7NZbTXlUNlFuchw==[/tex],证明:[tex=6.429x2.571]rm7zD5pwKFBJdXdBRwnk7rleaMmcIMUR8tad0H3bQInhnpUJ47WgbWe+CPR0HKk5x9xNpkXKVMZ9im6SL9G+Mg==[/tex]
  • 证明:根据题意,构造利润函数:[tex=23.429x1.357]s2V+tTeHS6UyKgz/ERl8b3FEwW560uvnU3bVYRw/43aYvT7E9RgAaiZ6eCfUIjmx25iSpFHrFB55kf1ZDwjgChBOKshzi08FQoXFcrJe1iU=[/tex]就利润函数分别对资本K和劳动L求偏导数,并令其为零,得[tex=29.786x2.714]PZiPS6l836857VElt4Rv0MctQ96/U7Ewuo9kvPF/DK3LVkeOh1XkbmvYeEW6REDKDiMYPUoZzBqdfxiJCJPBwT9RYCIW8sWu56NToFn5HYCj0NQvTC87m2FGOxijfFTABzKDTPFR4u59xHNxqg6ApIOPPSS8MK/UyXdSDtUXTgvH4+1U1mk8TR+BP18KLapIzR/L2uN9gIgC6L1tZhxFOMXwDMmHQ674veTpeB29R4thWda5cEJD7LNVilxuyX9clJeLjnrDsZyLzuSDe86Hktb3JGq9o+ZDeyN7FmMRO90=[/tex][tex=29.143x2.643]PZiPS6l836857VElt4Rv0IIR28pE+F1zoNBhwJkC9hEbFXRxhYFGyR1ez33wZ925IfICF08+L7M/4MKeB2TeRlgGcEaEXJz+eEI70yyY9GM/9lxsaF5j1p/xtWjuHZ1lj0AmQRtpKkMpNCptSRsxDRx/7dbJP7etKhNvWFKyJcWoVQ1LBKo9Y/3bfNa8cZWu2HeCiNLvd39cDIg8xKKxlF2qwlW/FGc3OeHHp1Ko31+LX1fbcSKM969kE1sE7O9cK6G5uu79eXXStrHDCdJjgQ==[/tex]从而有:[tex=22.214x2.786]9vdUHsodua/cGIsF6lfm+XfKGc16BkDDHWzXzN5TmCjdTLQGrSSZQbZ7BIyxUxbk8upefSPvBcbf4FrbwY1nHaqwExF8pOP1Ly9FVpnEEdyXC5lmibzRB1TQOJCNotLZ/f02X4vrTUZceLVvi9whsp/8hTWnGe/lzGyR+/QGl7zoPcAkT0NvPFMA9aGe+SJQgAUEdF1Jb2bMk38GSuvqWw==[/tex]①[tex=21.786x2.786]9vdUHsodua/cGIsF6lfm+XfKGc16BkDDHWzXzN5TmCjdTLQGrSSZQbZ7BIyxUxbk8upefSPvBcbf4FrbwY1nHaqwExF8pOP1Ly9FVpnEEdxWRTAGGOZ6o/J4MVrSu9OB0xNdBBC/oM+vRXyBBr5wC/1S6BF8izaxCz4bxoEs1mGRG1zhVQHV8DdDT3N8+Zu1wzs2lTtTFGL6MUrQzQtRWA==[/tex]②②/①得[tex=10.857x3.357]rm7zD5pwKFBJdXdBRwnk7rh5KI2CfPT3R4N7UmVjS5ZIOumls2Sm/M1/UXPsrlRUvQzXTt22+MkQT1ZoD7fsTAZts269urmA+pfuCg7hxE0pMbXU2yZNYda6C95XK9bMjeBRN/Q3q4UPHrCtG36OWbKymLTqss+RZYIARspTumCWn9b1BOlyJ0xLXIHZ3ui8[/tex],即[tex=6.429x2.571]rm7zD5pwKFBJdXdBRwnk7rleaMmcIMUR8tad0H3bQInhnpUJ47WgbWe+CPR0HKk5x9xNpkXKVMZ9im6SL9G+Mg==[/tex]

    内容

    • 0

      设DES加密算法中的一个S盒为: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 1 2 3 14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7 0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8 4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0 15 12 8 2 4 9 1 7 5 11 A: 1010 B: 0001 C: 1011 D: 0111

    • 1

      下面语句的输出结果是?range(len('HelloWorld')) A: [1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11] B: 11 C: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] D: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

    • 2

      下面是图的拓扑排序的是?(多选)[img src="https://i1.chinesemooc.org/course/formula/201610/eb69927aaf8baae83211ee3fadf836e7.png"] A: 2 8 0 7 1 3 5 6 4 9 10 11 12 B: 2 8 7 0 6 9 11 12 10 1 3 5 4 C: 8 2 7 3 0 6 1 5 4 9 10 11 12 D: 8 2 7 0 6 9 10 11 12 1 3 5 4

    • 3

      not 1 or 0 and 1 or 3 and 4 or 5 and 6 or 7 and 8 and 9的值为

    • 4

      当执行下面的语句定义一维数组a后,此数组的所有元素为 ( ) inta[10]; A.a[1],a[2],a[3],a[4],a[5],a[6],a[8],a[9],a[10],a[10] B.a[0],a[1],a[2],a[3],a[4],a[5],a[6],a[7],a[8],a[9] C.a[0],a[2],a[3],a[4],a[5],a[6],a[7],a[8],a[9],a[10] D.a[1],a[2],a [3],a[4],a [5],a [9],a [7],a [8],a [9],a [10],a [11]