When will the meeting begin
A: At 1:30 p.m..
B: At 2:00 p.m..
C: At 2:30 p. m..
A: At 1:30 p.m..
B: At 2:00 p.m..
C: At 2:30 p. m..
C
举一反三
- When will the meeting begin A: At 1:30 p.m.. B. At 2:00 p.m.. B: At 2:30 p. m..
- Woman: When is the visit to the museum tomorrow? Is it at 8:30 in the morning?Man: No, it’s at 1:30 in the afternoon. The meeting is at 8:30.When will they visit the museum tomorrow?() A: At 8:30 a.m.. B: At 9:30 a.m.. C: At 1:30 p.m.. D: At 2:30 p.m..
- 求[2,1000]素数的个数,可以使用的命令有()。 A: m=2:1000; p=isprime(m); sum(p) B: p=primes(1000); length(p) C: m=2:1000; p=m(isprime(m)); length(p) D: m=2:1000; p=find(isprime(m)); length(p)
- 【单选题】设图中B点即变压器二次侧计算负荷为 P 30(2) 、 Q 30(2) ,则A点即变压器一次侧计算负荷 P 30(1) 、 Q 30(1) 为()。 A. P 30(1) = P 30(2) + ΔP T , Q 30(1) = Q 30(2) + ΔQ T B. P 30(1) = P 30(2) - ΔP T , Q 30(1) = Q 30(2) - ΔQ T C. P 30(1) = P 30(2) + ΔQ T , Q 30(1) = Q 30(2) + ΔP T D. P 30(1) = P 30(2) - ΔQ T , Q 30(1) = Q 30(2) - ΔP T
- 矩阵[left[ {egin{array}{*{20}{c}} { m{0}}&{ m{0}}&{ m{5}}&{ m{2}}\ { m{0}}&{ m{0}}&{ m{2}}&{ m{1}}\ { m{4}}&{ m{2}}&{ m{0}}&{ m{0}}\ { m{1}}&{ m{1}}&{ m{0}}&{ m{0}} end{array}} ight]]的逆矩阵为 ( ) </p></p>
内容
- 0
设P={1,2,3),M={1,3,5),则P\M=( ) A: {5} B: {2} C: {1} D: {3}
- 1
Func(int a, int b) {static int m=0,I=2; I+=m+1; m=I+a+b; return(m); } main() { int k=4,m=1,p; p=Func(k,m); printf(“%d”,p); p=Func(k,m);printf(“%d”,p); }
- 2
(53) A: m≥1,n≥1时,P(m,n)→P(m+1,n+1) B: m≥1,n≥1时,P(m,n)→P(m,n+1)以及P(m+1,n+1) C: m≥1,n≥1时,P(m,n)→P(m+1,n)以及P(m,n+1) D: n≥1时,P(1,n)→P(1,n+1);m≥1,n≥1时,P(m,n)→P(m+1,n+1)
- 3
()E() SA() S()P 为使上述三段论成立,括号中应填的字母按顺序是。 (1)P,M,M,O (2)M,P,M,E (3)P,M,M,E
- 4
M: When will the meeting beginW: According to the schedule it should be at 9:30.M: How long will it lastW: It will last for an hour and a half. When will the meeting be closed() A: 1:30 B: 11:00 C: 9:30 D: 10:00