在[tex=2.357x1.0]m5fKCA0WGhfJpuVc0VWfdw==[/tex]时,有电池:[tex=18.214x1.357]47pHpajQZSBuLLgBmriX+tBhhH0Gm1HCy9j/gLXqkSyWV+19Nm07dH5rjJ0m/PxPWAl6nF43zCd/6gb3xg6iTtcpDzedO+pW8j9jz0Ali+g=[/tex],已知化合物的标准生成Gibss自由能分别为:[tex=32.214x1.5]hGXI8IHY9x82srp80/KXR2MRbBsjEJOAQP0EmJp4gIEhLsjGuzNGutAQSnLFJE0ef/VZjMLAlsY1U+Kvkz9pnV8mzxdTssQsBw7/90VP1AdI41fLdliWCwqpv4SiPaWQBzoW/O35LSmfK8ORBoz2Xn4FbnNI8Sfq/1p8JQXaAsVDFKUhGzDN3iHpPcBs2H0H1hG2W2lVrc3DO2M97o1dEllAXn4hEtPo2+JmqHBLrT0=[/tex]。试计算电池的电动势。
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 在[tex=2.357x1.0]m5fKCA0WGhfJpuVc0VWfdw==[/tex]时,有电池:[tex=18.214x1.357]47pHpajQZSBuLLgBmriX+tBhhH0Gm1HCy9j/gLXqkSyWV+19Nm07dH5rjJ0m/PxPWAl6nF43zCd/6gb3xg6iTtcpDzedO+pW8j9jz0Ali+g=[/tex],已知化合物的标准生成Gibss自由能分别为:[tex=32.214x1.5]hGXI8IHY9x82srp80/KXR2MRbBsjEJOAQP0EmJp4gIEhLsjGuzNGutAQSnLFJE0ef/VZjMLAlsY1U+Kvkz9pnV8mzxdTssQsBw7/90VP1AdI41fLdliWCwqpv4SiPaWQBzoW/O35LSmfK8ORBoz2Xn4FbnNI8Sfq/1p8JQXaAsVDFKUhGzDN3iHpPcBs2H0H1hG2W2lVrc3DO2M97o1dEllAXn4hEtPo2+JmqHBLrT0=[/tex]。试写出该电池的电池反应。
- 在[tex=2.357x1.0]m5fKCA0WGhfJpuVc0VWfdw==[/tex]时,有电池:[tex=18.214x1.357]47pHpajQZSBuLLgBmriX+tBhhH0Gm1HCy9j/gLXqkSyWV+19Nm07dH5rjJ0m/PxPWAl6nF43zCd/6gb3xg6iTtcpDzedO+pW8j9jz0Ali+g=[/tex],已知化合物的标准生成Gibss自由能分别为:[tex=32.214x1.5]hGXI8IHY9x82srp80/KXR2MRbBsjEJOAQP0EmJp4gIEhLsjGuzNGutAQSnLFJE0ef/VZjMLAlsY1U+Kvkz9pnV8mzxdTssQsBw7/90VP1AdI41fLdliWCwqpv4SiPaWQBzoW/O35LSmfK8ORBoz2Xn4FbnNI8Sfq/1p8JQXaAsVDFKUhGzDN3iHpPcBs2H0H1hG2W2lVrc3DO2M97o1dEllAXn4hEtPo2+JmqHBLrT0=[/tex]。试写出该电池的电极反应。
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=