计算矩阵[img=132x71]1803073217452ab.png[/img]的Jordan标准型应使用的语句是
A: A={{5,4,3},{-1,0,-3},{1,-2,1}}; Decomposition[A]
B: A={{5,4,3},{-1,0,-3},{1,-2,1}}; LUDecomposition[A]
C: A={{5,4,3},{-1,0,-3},{1,-2,1}}; SchurDecomposition[A]
D: A={{5,4,3},{-1,0,-3},{1,-2,1}}; JordanDecomposition[A]
A: A={{5,4,3},{-1,0,-3},{1,-2,1}}; Decomposition[A]
B: A={{5,4,3},{-1,0,-3},{1,-2,1}}; LUDecomposition[A]
C: A={{5,4,3},{-1,0,-3},{1,-2,1}}; SchurDecomposition[A]
D: A={{5,4,3},{-1,0,-3},{1,-2,1}}; JordanDecomposition[A]
举一反三
- 【单选题】如图示代码,下面哪个是正确的输出结果 A. 0 1 2 3 4 5 B. 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 C. 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 D. 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5 0 1 2 3 4 5
- 【单选题】Which of the following matrices does not have the same determinant of matrix B: [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -1, 0, -9,-5] A. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 0; -1, 0, -9, -5] B. [1, 3, 0, 2; -2, -5, 7, 4; 1, 0, 9, 5; -1, 0, -9, -5] C. [1, 3, 0, 2; -2, -5, 7, 4; 3, 5, 2, 1; -3, -5, -2, -1] D. [1, 3, 0, 2; -2, -5, 7, 4; 0, 0, 0, 1; -1, 0, -9, -5]
- 在Matlab中,若a=[4 -1 2; 3 1 0],则find(a>=2)的运算结果为( )。 A: 1 2 5 B: 1 3 4 C: 1 1 0 0 1 0 D: (1,2)(1,3)(2,1)
- range(5)表示的范围是_________。 A: [0, 1, 2, 3] B: [1, 2, 3, 4] C: [0, 1, 2, 3, 4] D: [1, 2, 3, 4, 5]
- 以下对二维数组a初始化正确的语句是_。 A: int a[2][ ]={{0 , 1 , 2}, {3 , 4 , 5}}; B: int a[ ][3]={{0, 1, 2}, {3, 4, 5}}; C: int a[2][4]={{0, 1 , 2}, {3 , 4}, {5}} D: int a[ ][3]={{0, 1, 2}, { }, {3, 4}};