class Tank { int level; } public class TestTank { public static void main(String[] args) { Tank t1 = new Tank(); Tank t2 = new Tank(); t1.level = 9; t2.level = 47; System.out.println("1: t1.level: " + t1.level + ", t2.level: " + t2.level); t1 = t2; System.out.println("2: t1.level: " + t1.level + ", t2.level: " + t2.level); t1.level = 27; System.out.println("3: t1.level: " + t1.level + ", t2.level: " + t2.level); } }
1: t1.level: 9, t2.level: 47 2: t1.level: 47, t2.level: 47 3: t1.level: 27, t2.level: 27
举一反三
- 【单选题】享有报价优先推荐和Popular Supplier标识的等级是? A. Level 4 B. Level 1 和 Level 2 C. Level 3 和Level 4 D. Level 1
- 中国大学MOOC: Abraham Maslow’s Hierarchy of Human Needs are: Level 1 Physical Needs, Level 2 Safety Needs, Level 3 Esteem Needs , Level 4 Social Needs and Level 5 Self-Realization Needs.
- The freshman year is the most difficult for all college students because ______. A: they don't know how to live on their own B: they don't know when to study at college level C: they don't know how to study at the college level D: they don't have enough time for study
- Read the passage again and choose the best answer to complete each statement.（1--8）1. The Exhibition Hall is on _______. A: Level 1 B: Level 2 C: Level 3
- 【多选题】若f 1 (t) = ɛ (-t) , f 2 (t) = e t ,则f 1 (t)* f 2 (t) = A. f 1 ꞌ (t)* f 2 (–1) (t) B. f 1 (–1) (t)* f 2 ꞌ (t) C. f 1 (t-3)* f 2 (t+3) D. f 1 (–3) (t)* f 2 ꞌꞌꞌ (t)
内容
- 0
A level gauge for a tank is to （）.
- 1
若向量组α1=（1，2，-1，-2）T，α2=（2，t，3，1）T，α3=（3，1，2，-1）T线性相关，则t=（）。 A: 1 B: 2 C: -2 D: -1
- 2
________<br/>means the level for which appropriate additional<br/>protective security measures shall be maintained for a period of time<br/>as a result of heightened risk of a security incident. A: Security level 1 B: Security level 2 C: Security level 3 D: Security level 4
- 3
分析下面的JavaScript代码段,输出结果是()varlevel=3;document.write(level==1?"优":level==2?"良":level==3?"中":level==4?"及":"差",""); A: 中 B: 3 C: 差 D: 良
- 4
齐次线性方程组的基础解系为（）。 A: α1=（1，1，1，0）T，α2=（-1，-1，1，0）T B: α1=（2，1，0，1）T，α2=（-1，-1，0）T C: α1=（1，1，1，0）T，α2=（1，0，0，1）T D: α1=（2，1，0，1）T，α2=（-2，-1，0，1）T