设z=arccot(x+y),则zy′等于:()
A: 1/[1+(x+y)]
B: -sec(x+y)/[1+(x+y)]
C: -1/[1+(x+y)]
D:
A: 1/[1+(x+y)]
B: -sec(x+y)/[1+(x+y)]
C: -1/[1+(x+y)]
D:
举一反三
- 设函数z=f(x,y)=xy/(x2+y2),则下列结论中不正确的是() A: f(1,y/x)=xy/(x+y) B: f(1,x/y)=xy/(x+y) C: f(1/x,1/y)=xy/(x+y) D: f(x+y,x-y)=xy/(x+y)
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- int x=1,y=2,z; z=(x!=y)? x+y : x;则z= ________ 。
- int x=1, y=2, z=0; z= x > y ? x+y : x; 则z= ( )
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