求证: 对于[tex=4.929x1.214]/+gDsj1Fh24ZDJ6KDOXIb6h9gVmlnN8/xyJojb/Sql4=[/tex]有[tex=16.714x1.357]0pANN1SVkCE/Lw6FMZG+REMRXQ+E9riNVO0rz5YIaKBFggBIj7YkbBbqE4dkkBnYHnCGZ0vl790Zu0ipMz2bymNdaET37F65ReAG7eDV4mAWWmNltbXm9a+mxpvXdalHnQilAgYd4RVtq/O55jdsAw==[/tex], [tex=13.786x1.357]0xBVfUtQ+9UL0Lb3fYOdobMKjmG5laDzjQo1eHuEnFvb2P9dP6yxxERoE88m+oV2p1nq/XF7XWyJuj57WUgyOuMVX1agfXGanqJyAQBkT5ilJRuOd6MVG8sSinsBzKUW[/tex].
举一反三
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']
- 【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 利用行列式的性质计算下列行列式的值1 2 0 0 02 5 0 0 0 9 8 1 2 37 6 4 5 65 4 7 8 9
- 下面语句的输出结果是？range(len('HelloWorld')) A: [1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11] B: 11 C: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] D: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]