• 2022-06-16
    电液转辙机无定位表示,定位向反位操纵不动,电机线圈1断线,以下现象符合该故障的是()。
    A: X2与X1间电压为AC105V
    B: X2与X3、X4间电压为AC0V
    C: XI与X3、X4间电压为AC0V
    D: XI与X3、X4间电压为AC105V
  • A,B,D

    举一反三

    内容

    • 0

      设总体X服从均值为1/2的指数分布, X1, X2, X3, X4为来自X的样本, 则X1, X2, X3, X4的联合概率密度为[img=445x103]180387e18db7cd2.png[/img]

    • 1

      X=(x1,x2,x3,x4)T=(0,0,6,4)T是约束条件3x1+2x2+x3=6,2x1+x2+x4=4,x1,x2,x3,x4≥0的一个可行解。()

    • 2

      继续上题,为了程序编写简洁,要给数据框x中的6列重新命名为x1,x2,x3,x4,x5,x6,应该使用的命令是() A: ColNames(x) <- c("x1","x2","x3","x4","x5","x6") B: Names(x) <- c("x1","x2","x3","x4","x5","x6") C: colnames(x) <- c("x1","x2","x3","x4","x5","x6") D: colname(x) <- c("x1","x2","x3","x4","x5","x6")

    • 3

      设总体X~N(μ,σ2),x1,x2,x3,x4为来自总体X的样本,且

    • 4

      已知向量α1=(1,3,3,5)^T,α2=(1,3,5,7)^T满足方程α1+2X=3α2,则X=(x1,x2,x3,x4)^T,这里,x1= ,x2= ,x3= ,x4= . (其中^T表示转置)