不考虑自旋时，n=4的氢原子能级，与之对应的正确的波函数是：
A: [img=31x23]180397a1a97c095.png[/img]
B: [img=31x23]180397a1b2013bd.png[/img]
C: [img=41x23]180397a1ba5f760.png[/img]
D: [img=51x23]180397a1c252964.png[/img]
E: [img=41x23]180397a1cae1faa.png[/img]
F: [img=41x23]180397a1d315e33.png[/img]
G: [img=31x23]180397a1dc41a7e.png[/img]
H: [img=41x23]180397a1e552839.png[/img]
I: [img=41x23]180397a1edeb4d3.png[/img]
J: [img=31x23]180397a1f6d0a3f.png[/img]
A: [img=31x23]180397a1a97c095.png[/img]
B: [img=31x23]180397a1b2013bd.png[/img]
C: [img=41x23]180397a1ba5f760.png[/img]
D: [img=51x23]180397a1c252964.png[/img]
E: [img=41x23]180397a1cae1faa.png[/img]
F: [img=41x23]180397a1d315e33.png[/img]
G: [img=31x23]180397a1dc41a7e.png[/img]
H: [img=41x23]180397a1e552839.png[/img]
I: [img=41x23]180397a1edeb4d3.png[/img]
J: [img=31x23]180397a1f6d0a3f.png[/img]
举一反三
- 已知D(X) = 2，D(Y) = 1，X和Y的相关系数[img=109x29]180357352f85f5d.png[/img].则D(2X+Y+1) = . A: 19/3 B: 23/3 C: 28/3 D: 31/3
- 设随机变量X服从均值为2的指数分布，X的分布函数为F(x)，数学期望为E(X)，方差为D(X)，则以下结果正确的是 A: [img=128x28]1802d3b369ab5fe.png[/img] B: D(X)=4 C: P(X<2︱X>1)=F(1) D: P(X>2︱X>1)= F(1) E: [img=112x27]1802d3b372fb534.png[/img] F: D(X)=E(X) G: P(X≤2︱X>1)= F(2) H: [img=82x27]1802d3b37bbbf05.png[/img]
- 设随机变量X服从均值为2的指数分布，X的分布函数为F(x)，数学期望为E(X)，方差为D(X)，则以下结果正确的是 A: [img=128x28]18034b986fbc78a.png[/img] B: D(X)=4 C: P(X<2︱X>1)=F(1) D: P(X>2︱X>1)= F(1) E: [img=112x27]18034b98781508a.png[/img] F: D(X)=E(X) G: P(X≤2︱X>1)= F(2) H: [img=82x27]18034b9880d080a.png[/img]
- 设随机变量X服从均值为2的指数分布，X的分布函数为F(x)，数学期望为E(X)，方差为D(X)，则以下结果正确的是 A: [img=128x28]18033e117e9725e.png[/img] B: D(X)=4 C: P(X<2︱X>1)=F(1) D: P(X>2︱X>1)= F(1) E: [img=112x27]18033e11879f263.png[/img] F: D(X)=E(X) G: P(X≤2︱X>1)= F(2) H: [img=82x27]18033e1190d2ef2.png[/img]
- 设随机变量X服从均值为2的指数分布，X的分布函数为F(x)，数学期望为E(X)，方差为D(X)，则以下结果正确的是 A: [img=128x28]18036372a260d4c.png[/img] B: D(X)=4 C: P(X<2︱X>1)=F(1) D: P(X>2︱X>1)= F(1) E: [img=112x27]18036372aa45c90.png[/img] F: D(X)=E(X) G: P(X≤2︱X>1)= F(2) H: [img=82x27]18036372b2a31e1.png[/img]