• 2022-06-18
    题 $3.5$ 图所示电路, 已知 [tex=5.214x1.5]qZ1Xf2a0JTGI2iK0NHylI+8myIeETgwOzLGad1sxNADdHi6aeUWnXfK95g49Es4y[/tex], 求电压[tex=1.714x1.357]PHQU/cbip4o9BavRUlPCmA==[/tex]。[img=455x158]17d17e3fc4dc9d9.png[/img]
  • 解 设各电流、电压参考方向如题解[tex=1.286x1.0]ykz3jgb2CJYn4wlxWKd/Ww==[/tex]图所示。由[tex=4.143x1.286]CInJHqn7Pu0UyvRUluJ8EX2ynwKr/bxyylI+K8Py0pM=[/tex]元件上的电压、电流关系及[tex=2.143x1.0]QwfYtJODkBqwa95LCjL83w==[/tex] 、[tex=2.214x1.0]SKxcvJYhHHcxK0ScsP8vHw==[/tex], 并结合本题电路结构特点, 分别求得[tex=18.357x8.643]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[/tex]所以电压[tex=17.786x1.5]qeW9nQYtr9A9no4iBeN5oXtvWcDchW2hnrF6jQAi6ytNi7E2EGrt3zI39EB4+ywhaqz1sRcgJPQIRh604uh4eze1lo1502znGzYVdlJEvcXk41zBqmHGVfxHFJe2hCJaAgyYMnyIfBtMAMBvQEJXXg==[/tex]

    内容

    • 0

      set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为? A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}

    • 1

      求题9 18图所示电路的零状态响应[tex=1.714x1.357]LQDjhWLbNBGk2tb5pbSofQ==[/tex]。[img=338x231]17d507608dd0680.png[/img]

    • 2

      >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']

    • 3

      以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)

    • 4

      阅读下面的JavaScript代码,输出结果是function f(y) {var x=y*y;return x;}for(x=0;x<; 5;x++) {y=f(x);document.writeln(y);} A: 0 1 4 9 16 25 B: 0 1 2 3 4 C: 答案都不对 D: 0 1 4 9 16