举一反三
- 交换m,n数值的方法 A: m,n=n,m B: n,m=m,n C: m,n=m,n D: n,m=n,m
- 【单选题】如果m>0,n<0,m<|n|,那么m,n,-m,-n的大小关系是() A. -n＞m＞-m＞n B. m＞n＞-m＞-n C. -n＞m＞n＞-m D. n＞m＞-n＞-m
- 定义：int m=5,n=3;则表达式m=(m=1,n=2,n-m)的值是
- 有以下程序#includemain(){intm,n;scanf("%d%d",&m,&n);while(m!=n){while(m>n){m=m-n;}while(n>m){n=n-m;}}printf("%d",m);}该程序的功能是 A: 计算m和n的最小公倍数 B: 计算m和n的最大公约数 C: c D: 找出m和n中的较大值
- 求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png
内容
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1、main() { int m,n; scanf("%d,%d",&m,&n); while(m!=n) { while(m>n) m=m-n; while(n>m) n=n-m; } printf("m=%d\n",m); }若输入7,3 ，程序的执行结果是__________若输入6,2 ，程序的执行结果是__________若输入9,6 ，程序的执行结果是__________
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求极限[img=144x45]1803d6afb8a008a.png[/img]的MATLAB程序为：syms x m n ay=(x^m-a^m)/(x^n-a^n)limit(y,x,a)计算结果为： A: (a^(m - n)*m)/n B: a^(m - n)*m/n C: 无法求值 D: a^(m - n)*m*n E: a^(m - n)/m/n F: (a^m - n)*m)/n
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设A与B为矩阵,AC=CB，C为m×n矩阵，则A与B分别是( )矩阵 A: n×m,m×n B: m×n,n×m C: n×n,m×m D: m×m,n×n
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用m ^ n表示幂函数[img=24x19]1803c46110028d2.png[/img]，下面哪些是正确定义？ A: m^0=0 m^n=m*m^(n-1) B: m^0=1 m^n=m*m^(n-1) C: m^0=0 m^n=m*m^n-1 D: m^1=0 m^n=n*m^(n-1)
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用m ^ n表示幂函数[img=24x19]17de86c77a4f1cd.png[/img]，下面哪些是正确定义？ A: m^0=0 m^n=m*m^(n-1) B: m^0=1 m^n=m*m^(n-1) C: m^0=0 m^n=m*m^n-1 D: m^1=0 m^n=n*m^(n-1)