目标函数[img=112x69]18034d6124e583c.png[/img]在写成lingo语句时的形式正确的是 A: max=sum(hello:a*x); B: max @sum(hello(i):a(i)*x(i)); C: max=sum(hello(i):a(i)*x(i)); D: max=@sum(hello:a*x);

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2022-06-19

目标函数[img=112x69]18034d6124e583c.png[/img]在写成lingo语句时的形式正确的是 A: max=sum(hello:ax); B: max @sum(hello(i):a(i)x(i)); C: max=sum(hello(i):a(i)x(i)); D: max=@sum(hello:ax);

目标函数[img=112x69]18034d6124e583c.png[/img]在写成lingo语句时的形式正确的是
A: max=sum(hello:a*x);
B: max @sum(hello(i):a(i)*x(i));
C: max=sum(hello(i):a(i)*x(i));
D: max=@sum(hello:a*x);

答案：

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举一反三

下面约束段语句表达正确的是 A: @for(wh(i):@sum(vd(j):x(i,j))<=a(i)); B: for(wh(i):@sum(vd(j):x(i,j))<=ai(i)); C: @for(wh(i):@sum(vd(j):x(i,j))<=a(i); D: @for(wh(i):sum(vd(j):x(i,j))<=ai(i));
下列程序运行时输入:20 30 5 85 40,运行结果为: #include #define N 5 int main(void) { int a[N],max,min,sum,i; for (i=0;i scanf("%d",&a[i]); sum=max=min=a[0]; for (i=1;i { sum+=a[i]; if (a[i]>max) max=a[i]; if (a[i] } printf("max=%d min=%d sum=%d aver=%4.2f ",max,min,sum,(float)(sum-max-min)/(N-2)); return 0; }
下面模型段语句表达错误的是 A: min=@sum(links(i,j):c(i,j)*x(i,j)); B: min=@sum(links:c*x); C: @for(vd(j):@sum(wh(i):x(i,j))=d(j)); D: @sum(vd(j):@for(wh(i):x(i,j))=d(j));
以下程序：void sum(int x){int i,sum=0;for (i=0;i<;5;i++){sum=sum+i;}x=sum;}main(){int x=90；sum(x);printf(“%d”,x);}执行后输出结果是_______。 A: 0 B: 10 C: 90 D: 100
以下四个选项中和下面代码功能相同的是（）。（选择一项） int i = 1; int sum = 0; while (i <= 100) { if (i % 2 == 0) sum = sum + i; i++; } A: for (int x =1; x<=100;x++){ sum=sum+x;} B: for (int x =0; x<=100;x+=2){ sum=sum+x;} C: for (int x =1; x<=100;x+=2){ sum=sum+x;} D: 上述全对