• 2022-06-15
    代数系统 [tex=3.429x1.357]dOdS9oTt8d627KTDGvWWtw==[/tex]定义如下:[tex=8.0x6.071]I08GkjPu5ilZ1cL3oVOjRDthbI6b9yBAb3FYfmWx9FVB2hL1r5K1ov8ijWjb4j3dIc5gclQL4uHwsbZdiP02cBveSlxsmIsQEmtdfuWbPigpHPNXKUuvY6lyC6Piq8SmgVIkDNsDqbVaaCaMce3tp9NhuC+wQ/Q4wa+pRbvn6bwWUziJyPli6hPB55gidqCb0lr7J1dhWHNxrEPtpWoGnh41n2MRY9ImuLCVL0Ca3WgglLL0NzUncKkDfT9pFZ1dQ2BCNaLrgNDzcn1suMaHOA==[/tex][tex=7.714x5.643]I08GkjPu5ilZ1cL3oVOjROvAfeDUalB11ixL4Nf3qb6/dwfQo6AWHDXxVrsHxBo4u2kvMAcbGmcHnCWRp97rBM3fVpJaYdUinjRA7CklEicRx8NZMR6ym5WO465IKBrv9syouyl1sPXBtlw58ZvHsfsOWhaEa0doiKT+EkNM8uIZjv5H8clIQyB7JZHOlrgBsLCVE4j2ABQ81T/FJWG3RAzofMO5NLzoYhvmOegDoOWeGHICMVXwLJqiyLYFPRxVGndWYrt62X5ygIMW0SiUFA==[/tex]证明:在[tex=3.429x1.357]dOdS9oTt8d627KTDGvWWtw==[/tex]中解下面方程组[tex=5.643x2.786]7EJHVCtO2IWq3KpdB+jQshTaqXo3Uympm4jwsW/qmipi9+bSbIt86pEFPvVXo19v/FDiPp/oc1SCkyteavXREtOye/NmkBTluPV1MJf26H0=[/tex]
  • 对方程组[tex=7.5x3.357]7EJHVCtO2IWq3KpdB+jQspQyxCrFynGsNG/t6jmN48ZIb1x1aCQsPwNWSR/ZH5l+E4FcyHR8tRtZyVDkS50AaqlNmT5zcBxMgZusfX+NqHU=[/tex](2)[tex=3.071x1.357]BLvaTsqDflI8Yzo9OgzUnw==[/tex](1)得[tex=7.429x4.143]v4jcdM75wY0ZodWprclGAyoqjR3fSdkwB7xj0KKzq/XU8yha+0P2f62kr2sO+/rQ318eWETirLOjCUiSVjsG7jrpw6nRSik2Wjpizx2Yfgc=[/tex]故方程组的解为[tex=3.571x2.786]7EJHVCtO2IWq3KpdB+jQsm9QSGDsoDJw+NQ8yyeohXj9OcAo+y6PacIjaBIiiZacvP2IU5jRhC2Btwc30oto7w==[/tex]

    举一反三

    内容

    • 0

      A=[1 2 3 4 5 6 7 8 9]A(5)=[]A=1 4 7 5 8 3 6 9

    • 1

      下面语句的输出结果是?range(len('HelloWorld')) A: [1, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11] B: 11 C: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] D: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

    • 2

      输出九九乘法表。 1*1=1 2*1=2 2*2=4 3*1=3 3*2=6 3*3=9 4*1=4 4*2=8 4*3=12 4*4=16 5*1=5 5*2=10 5*3=15 5*4=20 5*5=25 6*1=6 6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 7*1=7 7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 8*1=8 8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 9*1=9

    • 3

      下面是图的拓扑排序的是?(多选)[img=340x240]1802faef6ebcc2a.png[/img] A: 2 8 0 7 1 3 5 6 4 9 10 11 12 B: 2 8 7 0 6 9 11 12 10 1 3 5 4 C: 8 2 7 3 0 6 1 5 4 9 10 11 12 D: 8 2 7 0 6 9 10 11 12 1 3 5 4

    • 4

      以下程序段实现的输出是()。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9