电容三点式振荡器如图[tex=2.071x1.0]9utR16H0dkrRUD60XchLcp3EvOaj4njvHFvfM5+gsHI=[/tex] 所示, 已知 [tex=1.429x1.0]Ex4wpJIxD8l62cC55OycrA==[/tex] 谐振回路的空载品质因数[tex=2.571x1.214]KS+wKhXPPXd7ppYdobrTWQ==[/tex], 晶体管的输出电导 [tex=7.286x1.429]CBVlFUSa2Ph/o1c5PYQWn6az5f/old3tq0BqRiZeOOVGyLUANwpztGzbQ20Eclkd9igpA+jySoIj0Ho+geO3cA==[/tex], 输入电导 [tex=7.357x1.429]ewi9McMfw6oqhbwOWwtPTnLJXzl477j9a41uGkaKarjPbquqbrQ7Ri9PIPNxSC8pIC727q+vzPBMqOFKMTvIDQ==[/tex] 试求该振荡器的振荡频率 [tex=0.857x1.214]VOhpUZGmsyFK9/GlBHBkQg==[/tex], 并验证 [tex=5.143x1.286]eGZgXNTrc3m5m3liyQiGeyRn/dvKIgUjPPAly4+gbh+x2E+DLdwH8MrdT3e+9TnB[/tex] 时,电路能否起振[img=414x305]17d6bc8de6c0857.png[/img]

2022-06-15

电容三点式振荡器如图[tex=2.071x1.0]9utR16H0dkrRUD60XchLcp3EvOaj4njvHFvfM5+gsHI=[/tex] 所示, 已知 [tex=1.429x1.0]Ex4wpJIxD8l62cC55OycrA==[/tex] 谐振回路的空载品质因数[tex=2.571x1.214]KS+wKhXPPXd7ppYdobrTWQ==[/tex], 晶体管的输出电导 [tex=7.286x1.429]CBVlFUSa2Ph/o1c5PYQWn6az5f/old3tq0BqRiZeOOVGyLUANwpztGzbQ20Eclkd9igpA+jySoIj0Ho+geO3cA==[/tex], 输入电导 [tex=7.357x1.429]ewi9McMfw6oqhbwOWwtPTnLJXzl477j9a41uGkaKarjPbquqbrQ7Ri9PIPNxSC8pIC727q+vzPBMqOFKMTvIDQ==[/tex] 试求该振荡器的振荡频率 [tex=0.857x1.214]VOhpUZGmsyFK9/GlBHBkQg==[/tex], 并验证 [tex=5.143x1.286]eGZgXNTrc3m5m3liyQiGeyRn/dvKIgUjPPAly4+gbh+x2E+DLdwH8MrdT3e+9TnB[/tex] 时,电路能否起振[img=414x305]17d6bc8de6c0857.png[/img]

答案：

[解] (1)求振荡频率[tex=1.143x1.214]Q9aJzC/1sEAmXH2IovsbCg==[/tex] 由于[tex=15.786x2.571]sB6Lz7o4JTUjUn+UbRcdAnXZQxvjpqRZdICWt2pQ38mQIJHebQE2MjYDSgu4PTJYc6shQFZeaRPF5LX5SdVoVqrXO3VBGUo/uNxAKyAfbKcnoq4zqPuqi8HS7rOklj+3KkLvGOhfYr3WjvQSME5MUQ==[/tex]所以[tex=24.357x2.643]Q+shtqdxLXZqh6gnRyQSaNMiqkFhvbzkiQ50yxbpEOOgSCeow80FaBI6a8yoW2gguv6Yt4SEjlasW2DBKNurwKGgovYNHoeHlmcwdxoIbhkrkMbh8ejy94pkPyX7OHhwAWXE8vSz0/POlL/97zdIbIQQ+STsP90HlXG5MDMxrTM+CchChPrafzjBtsBX1Lc3[/tex]求振幅起振条件[tex=25.929x8.286]Iid4WPCSXMbVzzoEa8wHjAyBAiW8NY9VpMVsTLMtbGvWt8Od6MYR5kgg/e+Me2LXNZhVdlxEg1cxGdRx571n9YuZelW7vdnp3E0eTCWyMpDbc+MVFveYyfJLo/f9Lufv/TIEY/gUa+xbhRwapybd1bW9+Oq7vA9q2yP0I4+3rvrr+R8gzIhY+W73jCBABLygprMbicOQxZrhWXrtfbpL4JrHQhk0vpVBMaOYC1tFuh03rpU6fj1brswI+/0ta2pCGV9T8EReWmNkxD4nlcGR5qVP1elqoWN8s3VbSXfl5j1dwNGM+cs3bqhTuYS5YJEFjYrzxZrnlYI3TCj2zKW+DeUks/xd+s7KR6ojk78z1O/ova1NlbZHyjhyxEGykVihQD7rYqOtWVtYVbYWEH14zTf3vELGSU9Nfr0ZedXVv0eHkeeVaaIqvfqyLyv8aG1hIz6s22C60c+0J3RIp/63jA==[/tex][tex=38.143x2.929]hQ79RjTi5U/E3ckVsFj18jIY1J5AaYHwXHQJUJedF2Cj6Cvuk7DhoHRQWnu6ZOzA71zaHsLLJLKpxwsxRUcUis7ScnXCCnVzOf8nTHKxqZ2VyzPARWgLBqxVUM8VPjPwFJ1j+cpUlbNMMvJy1fJ8qiNe8cOqwlYnW/Ukd5eilUT7UubCSLvwYajmGdl1adCj3AOJ+cEldqAmxH8MOWbuLW5FQikOY+sAxnYD/LnYXtCdAd5SbEKbyGVKZBnJRI4E/UIOqQ/nA3PAc03xkbp8k2WaJoAV2jpZ9K+Z57ixic9Rd2ePpimDR8bEnJWXEsmmpr/D62Y4zdF0NcLSVYDT/w==[/tex][tex=22.571x5.786]Fv4qnxPNCj3eSSE2qi4S2rE0LET+72eYOXWck/YtQFfhVG2xdUL5hkcCxmz/DbqAntGHteq1QkJRAN5wHfphaF2HJraircs9WWzB1J3IfWpEgrh1qio18bWdwfTNCGNUiOdqD4lNc5yqi7hNyFkyHnaMKXQeVAX0tJrj7u0UmLIYEcjDrJHAtwwru3vItzM+3kbH0T7Cn2ZE4vZxZ2dtG1MW2yx/iRMIAKJUWAnKzMe5k36yyhVu5T+lItN1QwWV/IQaieuaRKEUUJM2mNstFJi8QQnESSKTtoDM0ILNBnY0KwFuaFNRXqp8YUKPKoSInxNjekvFXUXhF5h46koD9mtro4FoJrsPfuLlE+69j+uxPL8QueeYEeNkjdIFwSkBbWPT0hfXts32CkDgb5Rvjw1RizYtI1+M/UBAFGjEAb+94sCxOuEib0BLetS59AKY[/tex]故满足振幅起振条件

举一反三

内容

0
若要将一个长度为N=16的序列x(n)重新位倒序,作为某一FFT算法的输入,则位倒序后序列的样本序号为( )。 A: x(15), x(14), x(13), x(12), x(11), x(10), x(9), x(8), x(7), x(6),<br/>x(5), x(4), x(3), x(2), x(1), x(0) B: x(0), x(4), x(2), x(6), x(1), x(5), x(3), x(7), x(8), x(12), x(10),<br/>x(14), x(9), x(13), x(11), x(15) C: x(0), x(2), x(4), x(6), x(8), x(10), x(12), x(14), x(1), x(3), x(5),<br/>x(7), x(9), x(11), x(13), x(15) D: x(0), x(8), x(4), x(12), x(2), x(10), x(6), x(14), x(1), x(9), x(5),<br/>x(13), x(3), x(11), x(7), x(15)
1
[tex=22.0x1.357]LHJ+y85YXU3v8GHWdrdQw3Wkm42jO1uuQ9ReIJQjcZKuQS9dt8xQcTgSBjKkS3fb[/tex][color=#000000][b],[/b][/color][color=#000000][b]求 [/b][tex=3.143x1.214]oFObQtwM9vyjjWL7fjyhww==[/tex][/color][color=#000000][b]全不发生的概率.[/b][/color] A: 3/8 B: 7/9 C: 5/9 D: 5/8
2
以下创建数组的方式错误的是（） A: shortx[]；x={1，2，3，4，5，6}； B: shortx[]=newshort[6]；x[0]=9；x[1]=8；x[2]=7；x[3]=6；x[4]=5；x[5]=4； C: shortx[]=newshort[6]；intlen=x.length；for（inti=0；i
3
【阅读理解（选择）/完型填空】基于以下描述回答 1-2 题: 下表是 9 名评委对 10 名学生的毕业设计进行等级评定结果: 评委 A B C D E F G H I J 1 1 2 4 3 9 6 5 8 7 10 2 1 4 2 5 6 7 3 10 8 9 3 1 3 4 5 2 8 9 6 10 7 4 1 3 4 5 2 6 10 8 7 9 5 1 9 2 5 6 3 4 8 10 7 6 1 4 9 2 5 6 7 3 10 8 7 1 3 5 10 2 6 9 7 8 4 8 1 3 5 7 6 4 8 10 2 9 9 1 2 8 4 9 6 3 7 5 10
4
A=[1 2 3 4 5 6 7 8 9]A(5)=[]A=1 4 7 5 8 3 6 9