求解方程组[img=149x61]1803072d83cd19e.png[/img]的命令是
A: Solve[{4x^2-9y^2==15,2x-3y==5},{x,y}]
B: Solve[4x^2-9y^2==15,2x-3y==5,{x,y}]
C: Solve[4x^2-9y^2==15,2x-3y==5,{x,y}]
D: Solve[{4x^2-9y^2==15,2x-3y==5}]
A: Solve[{4x^2-9y^2==15,2x-3y==5},{x,y}]
B: Solve[4x^2-9y^2==15,2x-3y==5,{x,y}]
C: Solve[4x^2-9y^2==15,2x-3y==5,{x,y}]
D: Solve[{4x^2-9y^2==15,2x-3y==5}]
举一反三
- 求解方程组[img=218x63]1803072f0e0e849.png[/img]接近 (2,2) 的解 A: FindRoot[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,2},{y,2}] B: NSolve[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,2},{y,2}] C: FindRoot[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,y},{2,2}] D: FindRoots[{x^2+y^2=5Sqrt[x^2+y^2]-4x,y=x^2},{x,2},{y,2}]
- 求解方程组[img=218x63]1803072e5daced1.png[/img]接近 (2,2) 的解 A: NSolve[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,2},{y,2}] B: FindRoot[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,2},{y,2}] C: FindRoot[{x^2+y^2==5Sqrt[x^2+y^2]-4x,y==x^2},{x,y},{2,2}] D: FindRoots[{x^2+y^2=5Sqrt[x^2+y^2]-4x,y=x^2},{x,2},{y,2}]
- 应用Matlab软件计算行列式[img=110x88]17da5d7b00219d6.png[/img]为( ). A: x^2 - 6*x^2*y^2 + 8*x*y^3 - 3*y^4 B: x^3 - 6*x^2*y^2 + 8*x*y^3 - 3*y^4 C: x^4 - 6*x^2*y^2 + 8*x*y^3 - 3*y^4 D: x^5- 6*x^2*y^2 + 8*x*y^3 - 3*y^4
- 如下C程序的输出是什么？#include [stdio.h]void Func1 (int x, int y);void Func2 (int *x, int *y); int main() { int x = 3; int y = 4;Func1 (x, y); printf ("x = %d, y = %d\n", x, y);Func2(&x, &y); printf ("x = %d, y = %d\n", x, y);} void Func1 (int x, int y) { x = x + y; y = x - y; x = x - y; printf ("x = %d, y = %d\n", x, y);} void Func2 (int *x, int *y) { *x = *x + *y; *y = *x - *y; *x = *x - *y;;} A: x = 3, y = 4x = 3, y = 4x = 3, y = 4 B: x = 4, y = 3x = 4, y = 3x = 4, y = 3 C: x = 3, y = 4x = 3, y = 4x = 4, y = 3 D: x = 4, y = 3x = 3, y = 4x = 4, y = 3
- 下列选项中函数solve应用正确的是( )。 A: solve(3*x+4*y=0, 2*y^2+x=0, x, y) B: solve‘3*x+4*y=0’, ’2*y^2+x=0’, ’x’, ’y’ C: solve(‘3*x+4*y=0’, ’2*y^2+x=0’, ’x’, ’y’) D: solve(‘3*x+4*y=0’, ’2*y^2+x=0’, x, y)