MOV A,30HMOV A,#30HMOV 31H,R0MOV 31H,@R0
举一反三
- 假设(30H)=60H,(60H)=55H,则执行下列指令后,(A)=H,MOV R0,30HMOV A,@R0
- 指出下列指令的本质区别。 MOV A,30H MOV A,#30H MOV 31H,R0 MOV 31H,@R0
- 已知:(30H)=23H,(31H)=13H,(40H)=72H,(41H)=08H 执行: MOV A,30H ADD A,40H DA A MOV 30H,A MOV A,31H ADDC A,41H DA A MOV 31H,A 则结果为:(30H)=______H,(31H)=______H,(40H)=______H,(CY)=______。
- 已知(R0)=4BH,(A)=84H,片内RAM(4BH)=7FH,(40H)=20H,问执行序后,MOV A,@R0MOV @R0,40HMOV 40H,AMOV R0,#35H结果:(R0)= 、(A)= ,4BH= 、40H=
- 指出下列指令的本质区别。 MOV A,30H MOV A,#30H MOV 31H,R0