下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。#includemain(){intr,m,n;scanf("%d%d",&m,&n);if(m
A: 【1】r=m,m=n,n=r;【2】m%n;
B: 【1】m%n;【2】r=m,m=n,n=r;
C: 【1】r=m,m=n,n=r;【2】n%m;
D: 【1】n%m;【2】r=m,m=n,n=r;
A: 【1】r=m,m=n,n=r;【2】m%n;
B: 【1】m%n;【2】r=m,m=n,n=r;
C: 【1】r=m,m=n,n=r;【2】n%m;
D: 【1】n%m;【2】r=m,m=n,n=r;
举一反三
- 下面程序的功能是用“辗转相除法”求两个正整数的最大公约数。请分析程序填空。 #include main() {int r,m,n; scanf("%d%d",&m,&n); if(m 【1】r=m,m=n,n=r;【2】m%n;
- 求给定自然数m和n的最大公约数。请完善程序。 Private Sub Command1_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop Until__________ Text3.Text = m End Sub Private Sub Command2_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do Until _______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sub Private Sub Command3_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r Do r = m Mod n m = n n = r Loop While________ Text3.Text =______ End Sub Private Sub Command4_Click() Dim m As Integer, n As Integer, r As Integer m = Text1.Text n = Text2.Text If m < n Then r = m: m = n: n = r r = m Mod n Do While______ m = n n = r r = m Mod n Loop Text3.Text =____ End Sube73f1fd63959cc8362d8c82d419c2353.png
- 以下程序是求整数m,n的最大公约数和最小公倍数，请补充完整： int gys(m,n) int m,n; { int t,r; if(m 第一空： m=n 第二空： r=m%n 第三空： n=r 第四空： gys(m,n)
- 设集合M={x∣x<2},集合N={x∣0 A: M∪N=R B: M∪СRN=R C: N∪СRM=R D: M∩N=M
- 设A为m×n矩阵，B为n×，n矩阵，若AB=E，则( ) A: r(A)=m，r(B)=m B: r(A)=m，r(B)=n C: r(A)=n,r(B)=m D: r(A)=n，r(B)=n