写出以下对称矩阵[tex=0.929x1.0]k/Cj2RiKlvftjUNiBSOakw==[/tex].对应的二次型[tex=4.0x1.429]ZHEmmDVybbEdLB7jzVGghjjyJuM7G5KBY66MujSJnIKabZyP0Ix0Pw/y8aLzuUN0[/tex][tex=9.143x3.643]+HNIZcMaSzNwCe0LO7bsUtE7T/ezT3heRoWANqpeD08hLtyOdX7t5kJmwJRmYBOM+mPEl801g3Sf8YbeZnMw8oaSoNoBVrfrhZbETM86f+3poVeqKYFotK5U179e/QKv/o8KdUpumju+hUCP/84T+Q==[/tex]
举一反三
- 写出以下对称矩阵[tex=0.929x1.0]k/Cj2RiKlvftjUNiBSOakw==[/tex].对应的二次型[tex=4.0x1.429]ZHEmmDVybbEdLB7jzVGghjjyJuM7G5KBY66MujSJnIKabZyP0Ix0Pw/y8aLzuUN0[/tex][tex=6.286x2.786]+HNIZcMaSzNwCe0LO7bsUtE7T/ezT3heRoWANqpeD0+jc8LYEST2zow1W7cTLlo36gbLVL5qOlzHtjEIP8mFkyhSBNC5hP1usWvMGHzizD8=[/tex]
- 下列程序段的执行结果是（ ）。 x = 5: y = 7: z = 8 If x < y Then t = x: x = y: y = t End If If y < z Then t = y: y = z: z = t If x < y Then t = x: x = y: y = t End If End If Print x, y, z A: 8 5 7 B: 8 7 5 C: 5 7 8 D: 7 5 8
- set1 = {x for x in range(10)} print(set1) 以上代码的运行结果为？ A: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} B: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9,10} C: {1, 2, 3, 4, 5, 6, 7, 8, 9} D: {1, 2, 3, 4, 5, 6, 7, 8, 9,10}
- 假设“☆”是一种新的运算，若3☆2=3×4，6☆3=6×7×8，x☆4=840(x＞0)，那么x等于： A: 2 B: 3 C: 4 D: 5 E: 6 F: 7 G: 8 H: 9
- >>>x= [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9]>>>print(x.sort()) 语句运行结果正确的是( )。 A: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] B: [10, 6, 0, 1, 7, 4, 3, 2, 8, 5, 9] C: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0] D: ['2', '4', '0', '6', '10', '7', '8', '3', '9', '1', '5']