lim[(5n^3-7n^2+1)/(n-1)^2]n→∞
举一反三
- 不确定度u={∑[(λi-λ)^2]/[n(n-1)]}^(1/2)这个公式的n是什么物理量?
- 以下能正确定义数组并正确赋初值的语句是A. int n=5,b[n][n]; B. int a[1][2]={{1},{3}};C. int c[2][]={{1,2},{3,4}};D. int a[3][2]={{1,2},{3,4}}; A: int n=5,b[n][n]; B: int a[1][2]={{1},{3}}; C: int c[2][]={{1,2},{3,4}}; D: int a[3][2]={{1,2},{3,4}};
- 计算下列极限:(1)lim(√n+1-√n)(2)lim√n(√n+1-√n)
- 如何解数列s(n)=(n-1)[s(n-1)+s(n-2)],s(1)=0,s(2)=1,求s(n)
- 设`\n`阶方阵`\A`满足`\|A| = 2`,则`\|A^TA| = ,|A^{ - 1}| = ,| A^ ** | = ,| (A^ ** )^ ** | = ,|(A^ ** )^{ - 1} + A| = ,| A^{ - 1}(A^ ** + A^{ - 1})A| = `分别等于( ) A: \[4,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] B: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n + 1)}^2}}},2{(\frac{3}{2})^n},\frac{{{3^n}}}{2}\] C: \[4,\frac{1}{2},{2^{n + 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\] D: \[2,\frac{1}{2},{2^{n - 1}},{2^{{{(n - 1)}^2}}},2{(\frac{3}{2})^{n - 1}},\frac{{{3^n}}}{2}\]