• 2022-06-16
    NSMutableDictionary *mutableDic = [NSMutableDictionary dictionaryWithObjectsAndKeys:@"lisi",@"name",[NSNumber numberWithInt:20],@"age", nil];
    [mutableDic setObject:@"89" forKey:@"num"];
    NSLog(@"mutableDic4 = %@“,mutableDic);
    控制台打印是:
    A: name = lisi;num = 89
    B: age = 20;name = lisi;num = 89
    C: age = 20;name = lisi
    D: age = 20
  • B

    举一反三

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    • 0

      HTML 代码:[br][/br][input name="man-news" /][br][/br][input name="milkman" /][br][/br][input name="letterman2" /][br][/br][input name="newmilk" /][br][/br]jQuery 代码: $("input[name*='man']") 结果:( )本题只有1个标准答案。 A: [] B: [] C: [] D: [ , , ]

    • 1

      下列( )方法定义和调用的代码是正确的。 A: static void Introduce(string gender = "男", string name, int age = 18){} Introduce(name: "alex", age: 20); B: static void Introduce(string name, int age = 18, string gender = "男"){} Introduce(age: 20, name: "alex"); C: static void Introduce(string gender = "男", string name, int ago = 18){} Introduce(age: 20, name: "alex"); D: static void Introduce(string name, int age = 18, string gender = "男"){}Introduce(name: "alex", age: 20);

    • 2

      以下变量定义,错误的是: A: struct student{int num, char name[20];} s; B: struct {int num, char name[20];} s; C: struct student{int num, char name[20];}; struct student s; D: struct student{int num, char name[20];} ; student s

    • 3

      ‍以下不合法的变量名是‎ A: name B: apple_price C: num D: *age

    • 4

      下列SQL语句中,能够实现“收回用户lisi对学生表(Stud)中年龄(Age)的修改权限”这一功能的是( )。 A: revoke update(Age) on table from lisi B: revoke update (Age) on table from public C: revoke update (Age) on Stud from lisi D: revoke update (Age) on Stud from public